Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 9 of 11.
Likitha said:
6 years ago
Thanks all for explaining clearly.
P.Dhana lakshmi said:
9 years ago
Nice explanations, Thank you all.
Krishna said:
1 decade ago
Why we used Tan please clarify ?
Vino said:
8 years ago
The value of √ 3 is 1.732.
Mari said:
7 years ago
The value of √3 is 1.732.
Mouli said:
1 decade ago
I am not understand jowy said.
Darshan said:
7 years ago
How will we get root3 = 1.73?
Anjali tevari said:
5 years ago
How to find √3 value?
(1)
Imtiyaz said:
9 years ago
How to find the root of 3?
Ravi said:
1 decade ago
Why we take AB/AC, AB/AD?
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