Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 8 of 11.
Yashish yenduva said:
2 years ago
By using tan we can easily get solution.
(4)
Ramya said:
7 years ago
Please explain me the solution clearly.
Kumar said:
4 years ago
For triangle, we use tan mostly. right.
(3)
Pradeep K Kerketta said:
1 decade ago
How can you manually calculate root 3?
Manisha said:
1 decade ago
Why we taken only tan? please explain.
Velraj vj.k said:
5 years ago
How to find √3? Please explain.
Amol meher said:
8 years ago
Why are uesd tan? Please explain me.
Sandy said:
9 years ago
How to take root 3? Please explain.
Rushikesh said:
7 years ago
How to find out the 100 * √3?
Bheemu said:
2 years ago
why tan 30°? Please explain me.
(13)
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