Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 9 of 11.
Amit m said:
8 years ago
Is there any other solutions that sin cos tan?
Yash said:
8 years ago
We can find AD, IF we use Tan then only we find AD. So we use tan. By using sin and cos also we can solve.
Darshan said:
7 years ago
How will we get root3 = 1.73?
Mari said:
7 years ago
The value of √3 is 1.732.
Manu said:
7 years ago
Why we are using tan instead of cos, can explain that?
Dileep said:
7 years ago
Why we to have use tan?
Shubham said:
7 years ago
Tan = perpendicular/Base, the value of perpendicular has been given and we have to find the base, that's why the tan is used.
Mky said:
7 years ago
Why we using only tan why not cot, sin, cos?
Akshay said:
7 years ago
Why two sides ac and ad are taken as opposite sides in a lighthouse although it is not given we can take another side also if we think in 3D?
Rushikesh said:
7 years ago
How to find out the 100 * √3?
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