Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 11 of 11.
Gopi said:
6 years ago
Why should you took tan angle why not take sin angle?
Velraj vj.k said:
5 years ago
How to find √3? Please explain.
Kanishka Roy said:
5 years ago
How do you decide which is the base and which is the height? Explain it, please.
Bhavarth said:
5 years ago
@Kanishka Roy.
The one which is opposite to angle will be height.
And one which is adjacent to angle will be base.
Note that the one which is the base is not the longest side of triangle otherwise it would be the hypotenuse.
The one which is opposite to angle will be height.
And one which is adjacent to angle will be base.
Note that the one which is the base is not the longest side of triangle otherwise it would be the hypotenuse.
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