Aptitude - Height and Distance - Discussion
Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Answer: Option
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships.
Then, AB = 100 m, 
ACB = 30° and ADB = 45°.
| AB | = tan 30° = | 1 |  AC = AB x 3 = 1003 m. |
| AC | 3 |
| AB | = tan 45° = 1 AD = AB = 100 m. |
| AD |
 CD = (AC + AD) |
= (1003 + 100) m |
| = 100(3 + 1) | |
| = (100 x 2.73) m | |
| = 273 m. |
Discussion:
104 comments Page 9 of 11.
Praket Mishra said:
6 years ago
Where we should use sin, cos, tan? Please anyone explain me.
(1)
Prasad said:
6 years ago
@All.
Know, how we get the 'tan'.
In the question is given we have to find the distance then that time we are not treating the angle of elevation so we have to take distance and hight then the formula becomes;
Tan=opp/adj.
Then AB/AC look at the figure it will be clear for you.
Know, how we get the 'tan'.
In the question is given we have to find the distance then that time we are not treating the angle of elevation so we have to take distance and hight then the formula becomes;
Tan=opp/adj.
Then AB/AC look at the figure it will be clear for you.
(1)
Velraj vj.k said:
5 years ago
How to find √3? Please explain.
Jambay said:
5 years ago
How come √3 + 1?
(1)
Yeshi samdup said:
5 years ago
Sine=opp/hyp.
Cos=adj/hyp..
Tan=opp/adj.
Tan30 = 100/CA.
CA = 100/tan30,
CA = 173.
Tan45 = 100/AD.
AD = 100/tan45,
AD = 100.
Therefore, CA+AD.
173+100.
=273.
Cos=adj/hyp..
Tan=opp/adj.
Tan30 = 100/CA.
CA = 100/tan30,
CA = 173.
Tan45 = 100/AD.
AD = 100/tan45,
AD = 100.
Therefore, CA+AD.
173+100.
=273.
(3)
Anjali tevari said:
5 years ago
How to find √3 value?
(1)
Kanishka Roy said:
5 years ago
How do you decide which is the base and which is the height? Explain it, please.
Bhavarth said:
5 years ago
@Kanishka Roy.
The one which is opposite to angle will be height.
And one which is adjacent to angle will be base.
Note that the one which is the base is not the longest side of triangle otherwise it would be the hypotenuse.
The one which is opposite to angle will be height.
And one which is adjacent to angle will be base.
Note that the one which is the base is not the longest side of triangle otherwise it would be the hypotenuse.
Mythili said:
4 years ago
@Yeshi Samdup
How?
CA = 100/tan30,
CA = 173.
Please explain this.
How?
CA = 100/tan30,
CA = 173.
Please explain this.
(2)
Anudeep said:
4 years ago
Why we are taking √3? Explain please.
(3)
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