Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
173 m
200 m
273 m
300 m
Answer: Option
Explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100 m, ACB = 30° and ADB = 45°.

AB = tan 30° = 1         AC = AB x 3 = 1003 m.
AC 3

AB = tan 45° = 1         AD = AB = 100 m.
AD

CD = (AC + AD) = (1003 + 100) m
= 100(3 + 1)
= (100 x 2.73) m
= 273 m.

Discussion:
104 comments Page 8 of 11.

Uttam Singh said:   7 years ago
We can use a Divide rule to find the root of any number.
(1)

Naveen said:   7 years ago
Why should we take tan? Anyone explain me.

Naveen said:   7 years ago
Why should we take tan? Anyone explain me.
(1)

Garalapati bharadwaja said:   7 years ago
Why should we take only tan? Anyone explain me.

Kishor said:   7 years ago
How? tan 45° = 1
AD = AB = 100 m. How it is? Explain in detail.

Kowsalyadevi said:   6 years ago
First, understand the problem from the given Diagram.

We have to find the distance of the CD.
So, first identify how to use 45° and 35°.
Only by using tan because we know AB value
We know that tanx = perpendicular/base.

tan 30° = AB/CA.
1/√3= 100/CA.
CA=100 x √3.
tan 45° = AB/AD.
1 = 100/AD,
AD = 100.
We know that CD = CA+CD.
= 100x√ 3+100,
= 100(√3+1),
= 100(1.73+1),
= 100(2.73),
= 273m.

Divakar said:   6 years ago
What is the reason to take tan? Please tell me.

Mrinayak said:   6 years ago
How to find the √3 value? Please explain the process.

Likitha said:   6 years ago
Thanks all for explaining clearly.

Gopi said:   6 years ago
Why should you took tan angle why not take sin angle?


Post your comments here:

Your comments will be displayed after verification.