Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 1)
1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
173 m
200 m
273 m
300 m
Answer: Option
Explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100 m, ACB = 30° and ADB = 45°.

AB = tan 30° = 1         AC = AB x 3 = 1003 m.
AC 3

AB = tan 45° = 1         AD = AB = 100 m.
AD

CD = (AC + AD) = (1003 + 100) m
= 100(3 + 1)
= (100 x 2.73) m
= 273 m.

Discussion:
104 comments Page 3 of 11.

Jambay said:   5 years ago
How come √3 + 1?
(1)

Anjali tevari said:   5 years ago
How to find √3 value?
(1)

Raksha said:   1 year ago
Why are we using tan 30°? Please explain to me.
(1)

Pooja said:   7 months ago
Simple explanation:

The formula of tan; θ is,
tan θ = opposite side/adjacent side
So, we have angles 30° and 45° and the opposite side 100 m.
So, we can find an adjacent side.
(1)

Sakshi said:   2 months ago
The right answer is 273m.
(1)

Ravi said:   1 decade ago
Why we take AB/AC, AB/AD?

Sam said:   1 decade ago
Just remember root3=1.73 and root2=1.41

we take ab/ac because we want to find ac and we only know ab thats it

Srikanth said:   1 decade ago
Why you taken Tan and why you not taken cos ?

Jowy said:   1 decade ago
The tan30 is root(3) divide by 3. So how did you get root(3) ?

Mouli said:   1 decade ago
I am not understand jowy said.


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