Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 7 of 15.

Chetan siyota said:   1 decade ago
Short trick if you have given difference between simple and compound interest,

SI-CI = P*square of (R/100).

Atanu said:   1 decade ago
Shortcut Method

sum = difference*(100/R)^2 for 2 year

sum = {difference*(100^3)}/{R^2*(300+R)} for 3 year

Aparna said:   1 decade ago
P(1+0.04)^2-P)-P*0.08.

From the above step how did you got that P(1/625) = 1.

Can you please explain me?

Rick said:   1 decade ago
You people should add the formula of C.I in the formula section which is missing.

C.I = p[(1+r/100)^n -1].

Sneha said:   8 years ago
Difference formula for 2 years____.
Sum = Difference * (100) ^/Rate^
Then, Sum = 1*100*100 / 4*4 =625.

Prudhvi said:   1 decade ago
Hai I'm prudhvi. Can any one help me out?

Why are we using 676/625x in the step one?

Please help me.

Yashika said:   8 years ago
The SI = CI when the principal and rate are the same and time is ________.

Please give me the answer.

Ritu said:   8 years ago
Please, someone explains the question. At what % per annum will 625 will amount to 676 in 2 yr at c.i.

ANUPAM DAS said:   9 years ago
We know that,

(C.I - S.I) = P * R * R/100 * 100.
HERE, 1 = P * 4 * 4/100 * 100.

P = 25 * 25 = 625.

Chinmoy Mondal said:   9 years ago
Very simple formula is;

p.(R/100)^2 = (compound interest - Simple interest) time duration 2 years.


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