Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 8 of 15.

AKSHAY said:   1 decade ago
The correct formula is (ci-si) (100/r) (100/r) = p.

NOTE: (THIS FORMULA IS FOR TWO YEARS ONLY).

Puneet said:   8 years ago
Anyone can please tell why we have to subtract x from C.I?

and 51x/625-2x/25=1 so x=625 how?

$weth@ said:   10 years ago
Is that a formula you used over there?

[x(1+4/100)2]-x? where and all we can use this?

Raja said:   1 decade ago
What is the shortcut formula to find differences of ci and si for 4 years and 5 years?

Shivesh said:   9 years ago
Derivation of this formula.

Principal x (r%/100)^2 = Difference between interests.

Nivash said:   2 years ago
Let the sum be Rs. x.
Then,
ci = (x(1 + r/100)^n - x ) why subtracting with x again?
(32)

Ankit said:   9 years ago
CI for 2 years - SI for 2 years = PR^2/100^2.
1 = P16/10000,
10000/16 = P,
P = 625.

Bhavani said:   6 years ago
S.P - C.I = 1.

p = 1 (100/4)^2.
= 1(100 x 100/4 x 4).
= 25 x 25.
= 625.

Ganga said:   1 decade ago
@Pankaj parashar.

Please tell me how CI rate for 2 years = 8.16%.

Please help me.

Revathi said:   8 years ago
CI-si=p(r/100)^2 this formula applicable for more than 2 yrs also.

Am I correct?


Post your comments here:

Your comments will be displayed after verification.