Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
135 comments Page 1 of 14.
SICI said:
4 weeks ago
In C. I = where -x is come from? Please explain me.
Joa said:
4 weeks ago
Thanks everyone for explaining the answer.
Saudagar Rokade said:
1 month ago
Diff = PR^²/10000.
1 = P×4^²/10000,
10000 = P×16,
P = 10000/16,
P = 625.
1 = P×4^²/10000,
10000 = P×16,
P = 10000/16,
P = 625.
(1)
Vanhel said:
2 months ago
SI = 8%.
CI = 8.16%.
CI - SI = 1.
8.16% - 8% = 1.
0.16% = 1.
Sum of the difference principal = 1/0.16 * 100 = 625.
CI = 8.16%.
CI - SI = 1.
8.16% - 8% = 1.
0.16% = 1.
Sum of the difference principal = 1/0.16 * 100 = 625.
(2)
P manoj said:
1 year ago
It is simply derived by using this formula => Diff =PR^2/100^2 -> It is only for 2 years difference.
Given -> Diff=1 , R =4, Tp find P?
By Formula ,
Diff = PR^2/100^2.
1 = P * 4 * 4/100 * 100.
1= P * 1/20 * 1/20.
Note : (Also for three years difference use this formula -> Diff = PR^2(300 + R)/100^3).
Given -> Diff=1 , R =4, Tp find P?
By Formula ,
Diff = PR^2/100^2.
1 = P * 4 * 4/100 * 100.
1= P * 1/20 * 1/20.
Note : (Also for three years difference use this formula -> Diff = PR^2(300 + R)/100^3).
(5)
Naveen said:
2 years ago
1=10000*x/4 * 4.
= 625.
= 625.
Kurdush said:
2 years ago
Shortcut to solve :
(100*100*Diff)/Rate * Rate.
here diff =1.
rate=4.
Substitute in above formula u get Rs.625.
(100*100*Diff)/Rate * Rate.
here diff =1.
rate=4.
Substitute in above formula u get Rs.625.
(3)
Madhav said:
2 years ago
Hi.
Before solving this question you have to be aware on S.I and C.I formula's.
S.I = PTR/100.
Where as AMOUNT = P (1+ R/100) ^T ====> IN C.I.
AMOUNT = P + C.I.
C.I = P (1+ R/100) ^T - P.
In the question, they give the difference between S.I AND C.I is rupee 1.
First Calculate S.I.
Let the PRINCIPAL or SUM be ==> '' P '', TIME = 2, RATE = 4%.
S.I = PTR/100 ==> P*2*4/100 ==> 2P/25.
Now C.I = P (1+R/100) - P ==> P (1+4/100) - P ==> 51P/625.
51P/625 - 2P/25 = 1.
LCM IS 625.
51P - 50P/625 = 1.
P = 625.
I hope this will be helpful.
Thank you.
Before solving this question you have to be aware on S.I and C.I formula's.
S.I = PTR/100.
Where as AMOUNT = P (1+ R/100) ^T ====> IN C.I.
AMOUNT = P + C.I.
C.I = P (1+ R/100) ^T - P.
In the question, they give the difference between S.I AND C.I is rupee 1.
First Calculate S.I.
Let the PRINCIPAL or SUM be ==> '' P '', TIME = 2, RATE = 4%.
S.I = PTR/100 ==> P*2*4/100 ==> 2P/25.
Now C.I = P (1+R/100) - P ==> P (1+4/100) - P ==> 51P/625.
51P/625 - 2P/25 = 1.
LCM IS 625.
51P - 50P/625 = 1.
P = 625.
I hope this will be helpful.
Thank you.
(23)
Mohit said:
2 years ago
How 51/625x came? Please explain.
(3)
Sumit said:
3 years ago
Diff = p(R/100) ^n.
By using this formula you can directly find the amount i.e. p.
1=p(4/100) ^2.
=> p=625.
By using this formula you can directly find the amount i.e. p.
1=p(4/100) ^2.
=> p=625.
(2)
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