Aptitude - Compound Interest
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- Compound Interest - Formulas
- Compound Interest - General Questions
- Compound Interest - Data Sufficiency 1
- Compound Interest - Data Sufficiency 2
- Compound Interest - Data Sufficiency 3.1
Amount |
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= Rs. 3321. |
C.I. = Rs. (3321 - 3200) = Rs. 121
Let the sum be Rs. x. Then,
C.I. = | ![]() |
x | ![]() |
1 + | 4 | ![]() |
2 | - x | ![]() |
= | ![]() |
676 | x | - x | ![]() |
= | 51 | x. |
100 | 625 | 625 |
S.I. = | ![]() |
x x 4 x 2 | ![]() |
= | 2x | . |
100 | 25 |
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51x | - | 2x | = 1 |
625 | 25 |
x = 625.
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
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100 x 60 | ![]() |
= 10% p.a. |
100 x 6 |
Now, P = Rs. 12000. T = 3 years and R = 10% p.a.
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= 3972. |

C.I. when interest compounded yearly |
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= Rs. 5304. |
C.I. when interest is compounded half-yearly |
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= Rs. 5306.04 |
Difference = Rs. (5306.04 - 5304) = Rs. 2.04
Amount = Rs. (30000 + 4347) = Rs. 34347.
Let the time be n years.
Then, 30000 | ![]() |
1 + | 7 | ![]() |
n | = 34347 |
100 |
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107 | ![]() |
n | = | 34347 | = | 11449 | = | ![]() |
107 | ![]() |
2 |
100 | 30000 | 10000 | 100 |
n = 2 years.