Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 5)
5.
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is:
Answer: Option
Explanation:
Amount = Rs. (30000 + 4347) = Rs. 34347.
Let the time be n years.
Then, 30000 | ![]() |
1 + | 7 | ![]() |
n | = 34347 |
100 |
![]() |
![]() |
107 | ![]() |
n | = | 34347 | = | 11449 | = | ![]() |
107 | ![]() |
2 |
100 | 30000 | 10000 | 100 |
n = 2 years.
Discussion:
46 comments Page 1 of 5.
AKASH KADAM said:
4 days ago
Given.
Compound interest = 7%.
Principle amount = 30000.
The final amount after receiving the interest is 4347.
So calculate the interest for the first year.
= 30000/100 * 7 = 2100 rs.
Now, calculate the compound interest.
for 1 year = 2100.
for 2 year= 2247.
for 3 year = 157.29.
Now add those.
2100 + 2247 + 157.29.
So the addition of the first two interest answer is 4347.
That is why the answer is 2.
Compound interest = 7%.
Principle amount = 30000.
The final amount after receiving the interest is 4347.
So calculate the interest for the first year.
= 30000/100 * 7 = 2100 rs.
Now, calculate the compound interest.
for 1 year = 2100.
for 2 year= 2247.
for 3 year = 157.29.
Now add those.
2100 + 2247 + 157.29.
So the addition of the first two interest answer is 4347.
That is why the answer is 2.
Kinzang Thinley said:
1 year ago
To find the period in years, we need to use the formula for compound interest:
A = P(1 + r/n)^(nt).
Where:
A = Final amount.
P = Principal amount (Rs. 30,000).
r = Annual interest rate (7% or 0.07).
n = Number of times the interest is compounded per year (Generally compounded annually, so n=1)
t = time in years.
Given:
Compound interest (CI) = Rs. 4347.
Principal amount (P) = Rs. 30,000.
Rate of interest (r) = 7% or 0.07.
Number of times compounded per year (n) = 1.
We have to find time, t.
First, let's calculate the final amount using the formula:
A = P(1 + r/n)^(nt).
A = 30000(1 + 0.07/1)^(1*t).
4347=30000(1.07)^t.
Now, we solve for t by converting it into a logarithmic form by taking log on both sides.
log4347/log30000 = log(1.07)^t.
log((4347/30000) = log((1.07)^t).
t = log((4347/30000))/(log(107)).
t = 3 years.
A = P(1 + r/n)^(nt).
Where:
A = Final amount.
P = Principal amount (Rs. 30,000).
r = Annual interest rate (7% or 0.07).
n = Number of times the interest is compounded per year (Generally compounded annually, so n=1)
t = time in years.
Given:
Compound interest (CI) = Rs. 4347.
Principal amount (P) = Rs. 30,000.
Rate of interest (r) = 7% or 0.07.
Number of times compounded per year (n) = 1.
We have to find time, t.
First, let's calculate the final amount using the formula:
A = P(1 + r/n)^(nt).
A = 30000(1 + 0.07/1)^(1*t).
4347=30000(1.07)^t.
Now, we solve for t by converting it into a logarithmic form by taking log on both sides.
log4347/log30000 = log(1.07)^t.
log((4347/30000) = log((1.07)^t).
t = log((4347/30000))/(log(107)).
t = 3 years.
Soniya said:
2 years ago
Simple method :
Amount of Rs.30000 x 7/100 = 2100 first year
Next year we calculate compound interest so RS. 30000+2100 add the previous year's interest.
Rs.32100 x 7/100 = 2247 => second year interest.
First-year interest : Rs.2100
Second-year interest : Rs.2247
Total Rs.4347
So, the answer is 2 years.
Amount of Rs.30000 x 7/100 = 2100 first year
Next year we calculate compound interest so RS. 30000+2100 add the previous year's interest.
Rs.32100 x 7/100 = 2247 => second year interest.
First-year interest : Rs.2100
Second-year interest : Rs.2247
Total Rs.4347
So, the answer is 2 years.
(61)
Nitish said:
3 years ago
No @Garima.
You should write it as 107/100 which came by the basic addition method.
You should write it as 107/100 which came by the basic addition method.
(3)
Garima said:
4 years ago
Can anyone please tell me how (1+7/100) become (107+100)?
(5)
Saron said:
4 years ago
Very good, Thanks everyone for explaining.
(2)
Migma Tshering Tamang said:
5 years ago
34347=30000(1+0.07)^n.
1.1449=(1.07)^n.
Using log in both the side.
log1.1449=n * log1.07.
n=log1.1449/log1.07.
n=2 years.
1.1449=(1.07)^n.
Using log in both the side.
log1.1449=n * log1.07.
n=log1.1449/log1.07.
n=2 years.
(8)
Lokesh said:
6 years ago
Verify with given option.
CI =7 %
1ST YEAR 7%.
For 2nd year, it becomes 7.49
Total 14.49
If 100% = 30K.
Then 114.49 = ?
(114.49 * 30K)÷100.
And you will get 4347.
CI =7 %
1ST YEAR 7%.
For 2nd year, it becomes 7.49
Total 14.49
If 100% = 30K.
Then 114.49 = ?
(114.49 * 30K)÷100.
And you will get 4347.
(1)
Anomie said:
7 years ago
How did come 11449?
(1)
Bimla jarmwal said:
7 years ago
Please, anyone, explain the answer in detail to me.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers