Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 15 of 15.

Kusum said:   1 decade ago
Please any one tel me how to solve it in simple method.

Vivek said:   1 decade ago
How to solve very simple?

Krishna said:   1 decade ago
Hello friends!

The question is very easy . First know the diff b/w S.I. and C.I.

S.I. = P*T*R/100
Amount = S.I. + P

C.I. = Amount - P
Amount = P*((1 +(R/100))^ n) where (n= no of years)

Given that S.I. and C.I diff is 1rupee

and also given T=time =2 yrs , R=rate = 4%,
and he asked P ie Principal Amount.


So S.I. = P*2*4/100; = P*2/25;
C.I. = Amount - P

= P*(1+ (4/100))^2 - P

= P*(1 + (1/25))*2 - P
= P*((26/25)^2) - p
= P*(676/625) - p

= (P*676-P*625)/625
= (P*51)/625

WE KNOW S.I. = (P*2)/25

AND S.I.-C.I. = 1
HENCE
(P*2)/25 - (P*51)/625 = 1
BY SOLVING U GET
P = 625 RS

Prudhvi said:   1 decade ago
Hai I'm prudhvi. Can any one help me out?

Why are we using 676/625x in the step one?

Please help me.

Priyanka P. said:   1 decade ago
Its p*(x/100)^2 = ans.

p=amount
x=rate

Name said:   1 decade ago
P x 4/100 x 4/100 = 1

P = 25*25 = 625
(1)

Gutti said:   2 decades ago
You have any shortcut method to this.

Xyz said:   2 decades ago
CI = interest- sum............
observe problem 1 . CI= 3321-3200

Goutham said:   2 decades ago
Hai I am Goutham.

Can anyone help me out , why are we using -x in the step one..

Please help me out
Thanks in advance...
(1)


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