Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
C.I. = | ![]() |
x | ![]() |
1 + | 4 | ![]() |
2 | - x | ![]() |
= | ![]() |
676 | x | - x | ![]() |
= | 51 | x. |
100 | 625 | 625 |
S.I. = | ![]() |
x x 4 x 2 | ![]() |
= | 2x | . |
100 | 25 |
![]() |
51x | - | 2x | = 1 |
625 | 25 |
x = 625.
Discussion:
149 comments Page 15 of 15.
Kusum said:
1 decade ago
Please any one tel me how to solve it in simple method.
Vivek said:
1 decade ago
How to solve very simple?
Krishna said:
1 decade ago
Hello friends!
The question is very easy . First know the diff b/w S.I. and C.I.
S.I. = P*T*R/100
Amount = S.I. + P
C.I. = Amount - P
Amount = P*((1 +(R/100))^ n) where (n= no of years)
Given that S.I. and C.I diff is 1rupee
and also given T=time =2 yrs , R=rate = 4%,
and he asked P ie Principal Amount.
So S.I. = P*2*4/100; = P*2/25;
C.I. = Amount - P
= P*(1+ (4/100))^2 - P
= P*(1 + (1/25))*2 - P
= P*((26/25)^2) - p
= P*(676/625) - p
= (P*676-P*625)/625
= (P*51)/625
WE KNOW S.I. = (P*2)/25
AND S.I.-C.I. = 1
HENCE
(P*2)/25 - (P*51)/625 = 1
BY SOLVING U GET
P = 625 RS
The question is very easy . First know the diff b/w S.I. and C.I.
S.I. = P*T*R/100
Amount = S.I. + P
C.I. = Amount - P
Amount = P*((1 +(R/100))^ n) where (n= no of years)
Given that S.I. and C.I diff is 1rupee
and also given T=time =2 yrs , R=rate = 4%,
and he asked P ie Principal Amount.
So S.I. = P*2*4/100; = P*2/25;
C.I. = Amount - P
= P*(1+ (4/100))^2 - P
= P*(1 + (1/25))*2 - P
= P*((26/25)^2) - p
= P*(676/625) - p
= (P*676-P*625)/625
= (P*51)/625
WE KNOW S.I. = (P*2)/25
AND S.I.-C.I. = 1
HENCE
(P*2)/25 - (P*51)/625 = 1
BY SOLVING U GET
P = 625 RS
Prudhvi said:
1 decade ago
Hai I'm prudhvi. Can any one help me out?
Why are we using 676/625x in the step one?
Please help me.
Why are we using 676/625x in the step one?
Please help me.
Priyanka P. said:
1 decade ago
Its p*(x/100)^2 = ans.
p=amount
x=rate
p=amount
x=rate
Name said:
1 decade ago
P x 4/100 x 4/100 = 1
P = 25*25 = 625
P = 25*25 = 625
(1)
Gutti said:
2 decades ago
You have any shortcut method to this.
Xyz said:
2 decades ago
CI = interest- sum............
observe problem 1 . CI= 3321-3200
observe problem 1 . CI= 3321-3200
Goutham said:
2 decades ago
Hai I am Goutham.
Can anyone help me out , why are we using -x in the step one..
Please help me out
Thanks in advance...
Can anyone help me out , why are we using -x in the step one..
Please help me out
Thanks in advance...
(1)
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