Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
C.I. = | ![]() |
x | ![]() |
1 + | 4 | ![]() |
2 | - x | ![]() |
= | ![]() |
676 | x | - x | ![]() |
= | 51 | x. |
100 | 625 | 625 |
S.I. = | ![]() |
x x 4 x 2 | ![]() |
= | 2x | . |
100 | 25 |
![]() |
51x | - | 2x | = 1 |
625 | 25 |
x = 625.
Discussion:
149 comments Page 15 of 15.
Gourikrishna said:
6 years ago
Explain clearly the first step.
Lithin said:
9 years ago
Well said, Thank you @Muthuu.
Subhani said:
1 decade ago
Difference D = P(R*R)/10000.
Rahul said:
7 years ago
It is 1 * 100^2/4^2 = 625.
Vivek said:
1 decade ago
How to solve very simple?
Ravi said:
8 years ago
x (100/r)^2 = 1(100/4)^2.
Naveen said:
4 years ago
1=10000*x/4 * 4.
= 625.
= 625.
Shanti mishra said:
8 years ago
1/.16*100=625.
Raj said:
9 years ago
Why not R/2?
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