Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 14 of 15.
Name said:
1 decade ago
P x 4/100 x 4/100 = 1
P = 25*25 = 625
P = 25*25 = 625
(1)
Bhupathi raju said:
1 decade ago
Any easiest method solve this problem?
KarthicK said:
9 years ago
@Sudharsan.
Clear explanation Thanks.
Clear explanation Thanks.
Nilesh said:
8 years ago
How 51/625 comes? Please explain that.
Gutti said:
2 decades ago
You have any shortcut method to this.
Jyoti said:
9 years ago
P = D * 100^2/R^2 = 1*100^2/16 = 625.
Mithra said:
5 years ago
Excellent. Thanks all for explaining.
Arun said:
8 years ago
8.16-8=1;
0.16=1,
100=x,
x = 625.
0.16=1,
100=x,
x = 625.
Mohit said:
5 years ago
How 51/625x came? Please explain.
(3)
Vansh agre said:
8 years ago
Difference = P * R *R /100*100.
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