Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 13 of 15.
Hitesh said:
8 years ago
Why are we subtracting -x in the first part?
Priya said:
1 decade ago
C.I-S.I=P(R/100)^2
IS THIS FORMULA CORRECT?
IS THIS FORMULA CORRECT?
Siva nandi reddy said:
1 decade ago
For 3 years p=(d*100*100*100)/(r*r(r+300)).
Chandan said:
8 years ago
Here, sum= (difference * 10000)/rate squre.
Joa said:
2 years ago
Thanks everyone for explaining the answer.
(5)
Tamanna said:
1 decade ago
How we got 51/625? can any one explain ?
An aspirant said:
1 decade ago
Sum = Difference*(100) square/(r)square.
Siva said:
1 decade ago
Difference between 2 years = pr^2/100^2.
Anu said:
10 years ago
Krishna please solve last equation also.
Priyanka P. said:
1 decade ago
Its p*(x/100)^2 = ans.
p=amount
x=rate
p=amount
x=rate
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