Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 12 of 15.
Siva said:
1 decade ago
@sudharshan.
Rightly said, cleared because of you.
Rightly said, cleared because of you.
Siddu said:
6 years ago
P = ci - si/{r/100}2 use this formula to get answer.
SICI said:
2 years ago
In C. I = where -x is come from? Please explain me.
(24)
Ramesh said:
9 years ago
P = D[100/r] * 2.
P = 1[100 * 100/4 * 4].
P = 625.
P = 1[100 * 100/4 * 4].
P = 625.
Rishi said:
9 years ago
I guess X must be the principal but not the sum.
NARENDRA SINGH said:
7 years ago
DIFF * 100 * 100/R * R.
1 * 100 * 100/16 = 625.
1 * 100 * 100/16 = 625.
Siri said:
1 decade ago
Shortcut method: difference= sum (rate/100) ^2.
Hema said:
2 years ago
How does 51P come in CI? Please explain to me.
(3)
Dhairya adhikari said:
9 years ago
(SI -CI) for 2 year = (r/100)^2 * principal.
Komal bishnoi said:
7 years ago
D*100^2/r^2 = 1*100*100/4*4 = 10000/16 = 625.
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