Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 11 of 15.
Verma said:
5 years ago
Use this to get the answer.
Sum = X(100/r)^2.
where X = C.I - S.I.
Sum = X(100/r)^2.
where X = C.I - S.I.
(1)
Xyz said:
2 decades ago
CI = interest- sum............
observe problem 1 . CI= 3321-3200
observe problem 1 . CI= 3321-3200
Srikant Duppada said:
1 decade ago
FORMULA:
Principal x (r%/100)^2 = Difference between interests.
Principal x (r%/100)^2 = Difference between interests.
Anju Chimouriya said:
6 years ago
Why cannot we use the compound interest formula in this problem?
Akshay said:
8 years ago
You can simple try this formula.
P=(100/R)^t *( C.I - S.I ).
P=(100/R)^t *( C.I - S.I ).
Jojo said:
8 years ago
For this use equation.
P=[(difference)*(100)^2]/(rate)^2.
P=[(difference)*(100)^2]/(rate)^2.
Nitin said:
6 years ago
Difference =p*(r/100)^2,
1=p*(4/100)^2,
10000/16=P,
625=P.
1=p*(4/100)^2,
10000/16=P,
625=P.
Suresh said:
1 decade ago
Please tell me anyone why are subtract X from first step?
Ahana said:
8 years ago
Is there any formula for diff bw ci and si for 4 years ?
Kusum said:
1 decade ago
Please any one tel me how to solve it in simple method.
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