Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 10 of 15.
Hiten said:
8 years ago
Diff = pri*(r/100)sqr.
1 = x*(4/100)sqr,
1 = x*(1/25)sqr,
1 = x/625,
x=625.
1 = x*(4/100)sqr,
1 = x*(1/25)sqr,
1 = x/625,
x=625.
Anushka Chouhan said:
5 months ago
Here, use a simple formula for the difference of 2 years = (pr) ^ 2/10000.
Saudagar Rokade said:
2 years ago
Diff = PR^²/10000.
1 = P×4^²/10000,
10000 = P×16,
P = 10000/16,
P = 625.
1 = P×4^²/10000,
10000 = P×16,
P = 10000/16,
P = 625.
(9)
Priya said:
10 years ago
Should we take x as principle? Or we can take any other variable like P?
Fiza khan said:
9 years ago
Can anyone please explain to me how we get 51/625 x in the first answer?
RAJEEV said:
1 decade ago
A=P( 1+R/100)
C.I=A-P
DIFFERENCE OF CI AND S.I FOR X YEAR= P*(R/100)^X
C.I=A-P
DIFFERENCE OF CI AND S.I FOR X YEAR= P*(R/100)^X
V panindraa said:
1 decade ago
Sum = (10,000 * difference) / r*r.
THIS FORMULA IS FOR TWO YEARS ONLY.
THIS FORMULA IS FOR TWO YEARS ONLY.
Manaswini said:
10 years ago
I can't understand this please some one help me to understand this sum.
SAILAJA said:
1 decade ago
CI-SI=1,
T=2
R=4
P=?
SHORTCUT IS
CI-SI=P(R/1OO)^2
1=P(4/100)^2
P=625
T=2
R=4
P=?
SHORTCUT IS
CI-SI=P(R/1OO)^2
1=P(4/100)^2
P=625
Amit kumar said:
1 decade ago
Sum = difference(100/rate)^t (here t=2yrs).
Sum = 1(100/4)^2 = 625.
Sum = 1(100/4)^2 = 625.
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