Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 6 of 15.
Ankit gupta said:
1 decade ago
Apply formula :
CI-SI= p(r/100)^2 this formula works only for t=2 years;
CI-SI = p[(r/100)^3+3(r/100)^2] for t=3 years;
CI-SI= p(r/100)^2 this formula works only for t=2 years;
CI-SI = p[(r/100)^3+3(r/100)^2] for t=3 years;
Divya kumari said:
11 months ago
The difference between S.I and C.I for two years is P.r^ 2/100^2.
Use this formula;
1 = p.4 * 4/100*100.
= 625 Answer.
Use this formula;
1 = p.4 * 4/100*100.
= 625 Answer.
(2)
Vanhel said:
2 years ago
SI = 8%.
CI = 8.16%.
CI - SI = 1.
8.16% - 8% = 1.
0.16% = 1.
Sum of the difference principal = 1/0.16 * 100 = 625.
CI = 8.16%.
CI - SI = 1.
8.16% - 8% = 1.
0.16% = 1.
Sum of the difference principal = 1/0.16 * 100 = 625.
(15)
Prince said:
8 years ago
Easy question try pr^2/100^2 = difference when the time is given 2.
Pr^2 (300+r)/100^3 when the time is given 3yr.
Pr^2 (300+r)/100^3 when the time is given 3yr.
Pankaj parashar said:
1 decade ago
Short cut method:
si rate for 2 years=8%
ci rate for 2 years=8.16%
diff=.16% ie is equal to re 1
so 1/.16*100=625
si rate for 2 years=8%
ci rate for 2 years=8.16%
diff=.16% ie is equal to re 1
so 1/.16*100=625
Princess said:
9 years ago
Can anyone tell me how can we find the sum and rate when compound interest for two successive years are are given?
Kurdush said:
4 years ago
Shortcut to solve :
(100*100*Diff)/Rate * Rate.
here diff =1.
rate=4.
Substitute in above formula u get Rs.625.
(100*100*Diff)/Rate * Rate.
here diff =1.
rate=4.
Substitute in above formula u get Rs.625.
(5)
Sumit said:
5 years ago
Diff = p(R/100) ^n.
By using this formula you can directly find the amount i.e. p.
1=p(4/100) ^2.
=> p=625.
By using this formula you can directly find the amount i.e. p.
1=p(4/100) ^2.
=> p=625.
(3)
Ankit said:
9 years ago
Solution for CI on certain amount for 2 years is 2200 and 3 years is 3640. Find the rate?
Guys please help me.
Guys please help me.
(1)
Vishal kumar said:
1 decade ago
Shortcut method
Difference = (D*R^2)/100^2 for 2 year
Difference = {(D*R^2)(300+R)}/100^3 for 3 year.
Difference = (D*R^2)/100^2 for 2 year
Difference = {(D*R^2)(300+R)}/100^3 for 3 year.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers