Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
625
630
640
650
Answer: Option
Explanation:

Let the sum be Rs. x. Then,

C.I. = x 1 + 4 2 - x = 676 x - x = 51 x.
100 625 625

S.I. = x x 4 x 2 = 2x .
100 25

51x - 2x = 1
625 25

x = 625.

Discussion:
149 comments Page 5 of 15.

Monalisa said:   1 decade ago
Hey guys, I have a shortcut formula for such problem:

p = d*100^2/r^2 (only for 2 yrs).

Where p = principle.
d = difference.
r = rate.

Krunal bhut said:   9 years ago
Interest of interest of amount is difference between SI and CI at rate given,

4% of x = 0.04x,
4% of 0.04x = (0.04x)4/100 = 1,
x = 625.

Arun raj said:   9 years ago
CI - SI = P(r/100)square
P = principal,
R = rate = 4.
CI - SI = 1.

=>. 1 = p(4/100)square.
1= p(1/25)square,
1= p(1/625),
P = 625.

MANAS BISWAL said:   1 decade ago
(C.I)2 - (S.I)2 = 1.
SUCCESSIVE DISCOUNT(C.I) = 4+4(4*4/100) = 8.16.
(S.I) 4+4 = 8.
8.16-8 = 0.16 .
0.16/1*100 = 625.

Prasanna Karthik said:   9 years ago
We can use the direct formula for this one.

The difference after 2 years = PR^2/100^2.

Here, P - Principal, R - Interest of Rate.

Praveen said:   1 year ago
we have difference formula for this question and that is;
CI - SI = P(R/100)^2,
1 = P(4/100)^2,
1 = P(1/25)^2,
1 = P /625.
625 = P.
(20)

Viji said:   1 decade ago
shotcut method:
If you give the difference between si and ci for 2 years means,
4*4/100
=.16
1/.16*100
100/16*100
100/4*25
625

Manu said:   1 decade ago
The question is to find the sum of CI & SI. The answer we got is the principle, not the sum. Please correct if I am Wrong.

Goutham said:   2 decades ago
Hai I am Goutham.

Can anyone help me out , why are we using -x in the step one..

Please help me out
Thanks in advance...
(1)

Bhavani said:   6 years ago
Principal = X say.

C.I = Amount-Principal.
= {X[1+4/100]^2-X}.

S.I = [ X(4)(2)/100].


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