Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 9)
9.
At what angle the hands of a clock are inclined at 15 minutes past 5?
Answer: Option
Explanation:
| Angle traced by hour hand in | 21 | hrs = | ![]() |
360 | x | 21 | ![]() |
° | = | 157 | 1 | ° |
| 4 | 12 | 4 | 2 |
| Angle traced by min. hand in 15 min. = | ![]() |
360 | x 15 | ![]() |
° | = 90°. |
| 60 |
Required angle = |
![]() |
157 | 1 | ![]() |
° | - 90° = 67 | 1 | ° |
| 2 | 2 |
Discussion:
43 comments Page 3 of 5.
Santosh said:
1 decade ago
Answer is very simple.
Difference between the hour hand and minute hand is 60 deg but for every minute hour hand will move by 1/2deg and for 15 min hour hand is moved by 7.5 deg so total is 60+7.5 = 67.5 deg.
Difference between the hour hand and minute hand is 60 deg but for every minute hour hand will move by 1/2deg and for 15 min hour hand is moved by 7.5 deg so total is 60+7.5 = 67.5 deg.
Eshaal said:
1 decade ago
Find the angle of the hands at 12:40?
Shinu said:
1 decade ago
15 minute past 5.
Time is - 5.15.
In minute hand at 15 minute = 60 degree.
In hour hand at 15 minute.
Here each 1 mint the hour hand change. 5 degree.
So, at 15 m hour hand change = 15*.5 = 7.5 degree.
So, total degree is = 60+7.5 = 67.5 degree.
Time is - 5.15.
In minute hand at 15 minute = 60 degree.
In hour hand at 15 minute.
Here each 1 mint the hour hand change. 5 degree.
So, at 15 m hour hand change = 15*.5 = 7.5 degree.
So, total degree is = 60+7.5 = 67.5 degree.
Ganesh said:
1 decade ago
21/4 = 5 hr 15 min = 5(15/60) = 5(1/4) = ((5*4)+1)/4 = 21/4.
Tashu said:
1 decade ago
@Sagar.
If 5+15/60, then why again 15 minutes is considered separately and solved in the answer?
If 5+15/60, then why again 15 minutes is considered separately and solved in the answer?
Sagar naikar said:
1 decade ago
5+15/60 = 21/4 is correct.
Yogash joshi said:
1 decade ago
Total no of points between any two no in watch for hour is 6. And for minute is 5.
Then angle between any two points for hour is 5 degree. And such for minute is 6 degree.
So when hour needle move one point between any two no then minute needle move 6 degree so the angle between any two no like 4 to five be 30 degree.
So cover 5 degree (for hour) = 10 degree (for min).
So 1 degree = 2 degree.
So when min needle travel 1 degree then hour needle cover 1/2 degree.
So for 15 minute it will cover 15/2 = 7.5.
And degree from 3 to 5 be 60 degree.
So total = 60+7.5 = 67.5.
Then angle between any two points for hour is 5 degree. And such for minute is 6 degree.
So when hour needle move one point between any two no then minute needle move 6 degree so the angle between any two no like 4 to five be 30 degree.
So cover 5 degree (for hour) = 10 degree (for min).
So 1 degree = 2 degree.
So when min needle travel 1 degree then hour needle cover 1/2 degree.
So for 15 minute it will cover 15/2 = 7.5.
And degree from 3 to 5 be 60 degree.
So total = 60+7.5 = 67.5.
Radhika said:
1 decade ago
Using formula to calculate angle i.e. 1/2(60*h-11*m) where h is hour time and m is minute, angle can easily be calculated.
Ajay said:
1 decade ago
What is past 5? which means what?
Soumitra lohar said:
1 decade ago
Theta = 1/2(60*h-11*m) (formula).
Where h = hour and m = minute.
5.15 = 1/2(60*5-11*15).
= 1/2(300-165).
= 67.5.
Where h = hour and m = minute.
5.15 = 1/2(60*5-11*15).
= 1/2(300-165).
= 67.5.
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Required angle =