# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 9)
9.
At what angle the hands of a clock are inclined at 15 minutes past 5?
 58 1 ° 2
64°
 67 1 ° 2
 72 1 ° 2
Explanation:

 Angle traced by hour hand in 21 hrs = 360 x 21 ° = 157 1 ° 4 12 4 2

 Angle traced by min. hand in 15 min. = 360 x 15 ° = 90°. 60

 Required angle = 157 1 ° - 90° = 67 1 ° 2 2

Discussion:
41 comments Page 2 of 5.

Sri said:   6 years ago
How came 21/4?
(2)

Aarif said:   6 years ago
Use the formula.

=(11/2*min-30*hour),
11/2*15-30*5,
165/2-150,
135/2=67.5.

Jayasudhan said:   7 years ago
@ALL.

Multiply it with 6(360/60) and for hrs multiply it by 30 (360/12) here in this problem they said 15 min past 5.

So, 5.15 take 15 min alone and multiply it with 6 gives 90 and then take 5.15 fully convert that 15min into hrs so it 5(1/4) in mixed fraction by converting into proper fraction we have 21/4 then multiply it with 30 gives 157.5 subtract 90 from it gives answer 67.5.

Mithilesh Naphade said:   7 years ago
Best way to find the angle between hr and min hand is 30H - 5.5M.

Pramod Patil said:   7 years ago
Here We have to find angle between 5:15.
For 5 hours = 5 * 30 = 150,
for 15 min = 15 * 5.5 = 82.5,
Therefore 150 - 82.5 = 67.5.

Hema sri said:   8 years ago
They given what angle hands of a clock k 5hrs 15min.

Actually 60min = 30degree.
1min = 1/2degree.

So what is the degree of 15min?

So 15/2 = 7.5.

We add 60min in 7.5 degrees.

Dharani said:   8 years ago
@Neha.

How can you multiply 150 degree in place of 5? By formula its wrong.

Neha said:   8 years ago
30 * 150 - 11/2 * 15 = 67.5.

Santosh said:   8 years ago