# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 9)

9.

At what angle the hands of a clock are inclined at 15 minutes past 5?

Answer: Option

Explanation:

Angle traced by hour hand in | 21 | hrs = | 360 | x | 21 | ° | = | 157 | 1 | ° | ||

4 | 12 | 4 | 2 |

Angle traced by min. hand in 15 min. = | 360 | x 15 | ° | = 90°. | ||

60 |

Required angle = | 157 | 1 | ° | - 90° = 67 | 1 | ° | ||

2 | 2 |

Discussion:

41 comments Page 1 of 5.
Deepak menaria said:
5 years ago

5:15 time.

5 hr angle = 5x30 = 150.

15 min in hour =(15/60)x30 =7.5.

150+7.5=157.5.

In minute hand for 15 min.

Minute hand angle is 6 degree so,

For 15 min = 15x6 =90.

So,

157.5 - 90 = 67.5 degree, Answer.

5 hr angle = 5x30 = 150.

15 min in hour =(15/60)x30 =7.5.

150+7.5=157.5.

In minute hand for 15 min.

Minute hand angle is 6 degree so,

For 15 min = 15x6 =90.

So,

157.5 - 90 = 67.5 degree, Answer.

(5)

Richin said:
5 years ago

It's a simple logic.

Angle between two adjasent numbers is 30.

So for 5: 15, the hands of the clock will be in 3 and 5 but the hour hand will be moved a little from 5.

So we have to find that only. ie, angle b/w 3&5 is 60 (30+30).

60+ half of the given minute will be the answer.

ie, 60+ 15/2= 67.5.

1 minute is 1/2°

Angle between two adjasent numbers is 30.

So for 5: 15, the hands of the clock will be in 3 and 5 but the hour hand will be moved a little from 5.

So we have to find that only. ie, angle b/w 3&5 is 60 (30+30).

60+ half of the given minute will be the answer.

ie, 60+ 15/2= 67.5.

1 minute is 1/2°

(3)

Sri said:
6 years ago

How came 21/4?

(2)

Srikanth said:
1 year ago

11/2 *m -30*h.

= 11/2*15 -30 * 5.

= 165/2 -150,

= 82.5-150,

= 67.5.

= 11/2*15 -30 * 5.

= 165/2 -150,

= 82.5-150,

= 67.5.

(2)

Shraddha said:
2 years ago

Use the formula: 30*(H)-11/2*(M).

(2)

Laxmi Hosamani said:
3 years ago

30 * 5 - 11/2 = 67.5.

(2)

Alekhya said:
3 years ago

Just put the formula :

θ = abs | 30*(H) - 11/2* (M)|.

= 30*5 - 5.5 * 15,

= 67.5°.

θ = abs | 30*(H) - 11/2* (M)|.

= 30*5 - 5.5 * 15,

= 67.5°.

(2)

Srinitha said:
2 months ago

Use formula( d × 30 + min/2).

D = distance b/w 5 and 15 minutes = 2,

= 2 × 30 + 15/2.

= 60+7 1/2.

= 67 1/2.

D = distance b/w 5 and 15 minutes = 2,

= 2 × 30 + 15/2.

= 60+7 1/2.

= 67 1/2.

(1)

Deki Zangmo said:
4 years ago

We can use the below formula to find angle when the hour and minute values are given:

A=30H-5.5M.

H=5 M=15 as per the above questions;

So now we just have to substitute values in the formula

A=(30*5) -5.5*15.

150 - 82.5.

=67.5°.

A=30H-5.5M.

H=5 M=15 as per the above questions;

So now we just have to substitute values in the formula

A=(30*5) -5.5*15.

150 - 82.5.

=67.5°.

(1)

Udai said:
2 months ago

It is 5:15.

we can assume 15 as "3".

So 5-3 = 2*30+15/2= 60+7.5.

Answer= 67.5.

we can assume 15 as "3".

So 5-3 = 2*30+15/2= 60+7.5.

Answer= 67.5.

(1)

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