Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 9)
9.
At what angle the hands of a clock are inclined at 15 minutes past 5?
Answer: Option
Explanation:
| Angle traced by hour hand in | 21 | hrs = |  |
360 | x | 21 |  |
° | = | 157 | 1 | ° |
| 4 | 12 | 4 | 2 |
| Angle traced by min. hand in 15 min. = | |
360 | x 15 | |
° | = 90°. |
| 60 |
 Required angle = |
|
157 | 1 | |
° | - 90° = 67 | 1 | ° |
| 2 | 2 |
Discussion:
41 comments Page 1 of 5.
Srinitha said:
9 months ago
Use formula( d × 30 + min/2).
D = distance b/w 5 and 15 minutes = 2,
= 2 × 30 + 15/2.
= 60+7 1/2.
= 67 1/2.
D = distance b/w 5 and 15 minutes = 2,
= 2 × 30 + 15/2.
= 60+7 1/2.
= 67 1/2.
(3)
Udai said:
10 months ago
It is 5:15.
we can assume 15 as "3".
So 5-3 = 2*30+15/2= 60+7.5.
Answer= 67.5.
we can assume 15 as "3".
So 5-3 = 2*30+15/2= 60+7.5.
Answer= 67.5.
(1)
Srikanth said:
2 years ago
11/2 *m -30*h.
= 11/2*15 -30 * 5.
= 165/2 -150,
= 82.5-150,
= 67.5.
= 11/2*15 -30 * 5.
= 165/2 -150,
= 82.5-150,
= 67.5.
(5)
Shraddha said:
2 years ago
Use the formula: 30*(H)-11/2*(M).
(3)
Laxmi Hosamani said:
3 years ago
30 * 5 - 11/2 = 67.5.
(2)
Alekhya said:
4 years ago
Just put the formula :
θ = abs | 30*(H) - 11/2* (M)|.
= 30*5 - 5.5 * 15,
= 67.5°.
θ = abs | 30*(H) - 11/2* (M)|.
= 30*5 - 5.5 * 15,
= 67.5°.
(2)
Deki Zangmo said:
4 years ago
We can use the below formula to find angle when the hour and minute values are given:
A=30H-5.5M.
H=5 M=15 as per the above questions;
So now we just have to substitute values in the formula
A=(30*5) -5.5*15.
150 - 82.5.
=67.5°.
A=30H-5.5M.
H=5 M=15 as per the above questions;
So now we just have to substitute values in the formula
A=(30*5) -5.5*15.
150 - 82.5.
=67.5°.
(3)
Ibrahim Payak said:
5 years ago
Simply put this eq:
∠ = |60H-11M/2|.
= |60*5-11*15/2|,
= |300-165/2|,
= |135/2|,
= 67.5.
∠ = |60H-11M/2|.
= |60*5-11*15/2|,
= |300-165/2|,
= |135/2|,
= 67.5.
Deepak menaria said:
5 years ago
5:15 time.
5 hr angle = 5x30 = 150.
15 min in hour =(15/60)x30 =7.5.
150+7.5=157.5.
In minute hand for 15 min.
Minute hand angle is 6 degree so,
For 15 min = 15x6 =90.
So,
157.5 - 90 = 67.5 degree, Answer.
5 hr angle = 5x30 = 150.
15 min in hour =(15/60)x30 =7.5.
150+7.5=157.5.
In minute hand for 15 min.
Minute hand angle is 6 degree so,
For 15 min = 15x6 =90.
So,
157.5 - 90 = 67.5 degree, Answer.
(5)
Richin said:
6 years ago
It's a simple logic.
Angle between two adjasent numbers is 30.
So for 5: 15, the hands of the clock will be in 3 and 5 but the hour hand will be moved a little from 5.
So we have to find that only. ie, angle b/w 3&5 is 60 (30+30).
60+ half of the given minute will be the answer.
ie, 60+ 15/2= 67.5.
1 minute is 1/2°
Angle between two adjasent numbers is 30.
So for 5: 15, the hands of the clock will be in 3 and 5 but the hour hand will be moved a little from 5.
So we have to find that only. ie, angle b/w 3&5 is 60 (30+30).
60+ half of the given minute will be the answer.
ie, 60+ 15/2= 67.5.
1 minute is 1/2°
(3)
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