Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 9)
9.
At what angle the hands of a clock are inclined at 15 minutes past 5?
58 1 °
2
64°
67 1 °
2
72 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 21 hrs = 360 x 21 ° = 157 1 °
4 12 4 2

Angle traced by min. hand in 15 min. = 360 x 15 ° = 90°.
60

Required angle = 157 1 ° - 90° = 67 1 °
2 2

Discussion:
41 comments Page 1 of 5.

Guhan said:   1 decade ago
We can use the formula

Theta= (11(Minutes)/2)-30(Hour)

Rekha said:   1 decade ago
How came 21/4?

Nikhil said:   1 decade ago
21/4=5.25
0.25 is 1/4 part of 60min. i.e. 15min

Hare ram said:   1 decade ago
(11/2)*15-30*5=67.5

Vamshik said:   1 decade ago
I think (30*Hrs)-(11/2)*Mins is the correct formula for getting this answer.

Rezowan said:   1 decade ago
Please explain how this formula came?

Vasuroshan said:   1 decade ago
@ rekha

5 hrs and 15 min so

5+15/60=5+1/4

20+1/4=21/4

Rajiv said:   1 decade ago
Please explain how we are getting 21/4

If 15 min is 4th part of 60 min.

then how 21 comes.

Neha Mishra said:   1 decade ago
5:15, means hour hand is on 5 and minute hand is on 3.

Now, 360/12=30.

Angle between any two numbers on the clock is 30 degrees.

Now angle between 3 and 6 is 90 degree.

Angle between 6 and 5 is 30 degree.

Thus 90-30=60;.

Angle between 5 and 3 is approximately 60 degrees.

Rameez said:   1 decade ago
Please explain this to me.

Considering total as 360 degreee. And there are 12 segments. So each segment will have 30 degree.

As there are 2 segments between 3 and 5 so 2x30= 60.

So why 67.5?


Post your comments here:

Your comments will be displayed after verification.