Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 9)
9.
At what angle the hands of a clock are inclined at 15 minutes past 5?
58 1 °
2
64°
67 1 °
2
72 1 °
2
Answer: Option
Explanation:

Angle traced by hour hand in 21 hrs = 360 x 21 ° = 157 1 °
4 12 4 2

Angle traced by min. hand in 15 min. = 360 x 15 ° = 90°.
60

Required angle = 157 1 ° - 90° = 67 1 °
2 2

Discussion:
41 comments Page 1 of 5.

Yogash joshi said:   1 decade ago
Total no of points between any two no in watch for hour is 6. And for minute is 5.

Then angle between any two points for hour is 5 degree. And such for minute is 6 degree.

So when hour needle move one point between any two no then minute needle move 6 degree so the angle between any two no like 4 to five be 30 degree.

So cover 5 degree (for hour) = 10 degree (for min).
So 1 degree = 2 degree.

So when min needle travel 1 degree then hour needle cover 1/2 degree.
So for 15 minute it will cover 15/2 = 7.5.

And degree from 3 to 5 be 60 degree.
So total = 60+7.5 = 67.5.

Nikhil Agarkar said:   1 decade ago
Basic calculations first :

In 1 min Angle traced by Hr hand=1/2 degree.
And in 5 min angle traced by minute hand = 30 degree.

So now,

In 15 minutes hour hand movement = 15*1/2 degree=7.5degree
and distance between minute and hour hand at 5.15 O'clock is calculated as,

10 minutes + 7.5 degree(hour hand extra movement in 15 minutes).

So,

As per our calculations,

5 minutes => 30 degree (for minute hand).
10 minutes => 60 degree.

So,

(60+7.5) degree = 67.5 degree.

Jayasudhan said:   8 years ago
@ALL.

Multiply it with 6(360/60) and for hrs multiply it by 30 (360/12) here in this problem they said 15 min past 5.

So, 5.15 take 15 min alone and multiply it with 6 gives 90 and then take 5.15 fully convert that 15min into hrs so it 5(1/4) in mixed fraction by converting into proper fraction we have 21/4 then multiply it with 30 gives 157.5 subtract 90 from it gives answer 67.5.

Richin said:   6 years ago
It's a simple logic.

Angle between two adjasent numbers is 30.
So for 5: 15, the hands of the clock will be in 3 and 5 but the hour hand will be moved a little from 5.

So we have to find that only. ie, angle b/w 3&5 is 60 (30+30).
60+ half of the given minute will be the answer.
ie, 60+ 15/2= 67.5.

1 minute is 1/2°
(3)

Neha Mishra said:   1 decade ago
5:15, means hour hand is on 5 and minute hand is on 3.

Now, 360/12=30.

Angle between any two numbers on the clock is 30 degrees.

Now angle between 3 and 6 is 90 degree.

Angle between 6 and 5 is 30 degree.

Thus 90-30=60;.

Angle between 5 and 3 is approximately 60 degrees.

Shinu said:   9 years ago
15 minute past 5.

Time is - 5.15.

In minute hand at 15 minute = 60 degree.

In hour hand at 15 minute.

Here each 1 mint the hour hand change. 5 degree.

So, at 15 m hour hand change = 15*.5 = 7.5 degree.

So, total degree is = 60+7.5 = 67.5 degree.

Deki Zangmo said:   4 years ago
We can use the below formula to find angle when the hour and minute values are given:
A=30H-5.5M.

H=5 M=15 as per the above questions;

So now we just have to substitute values in the formula
A=(30*5) -5.5*15.
150 - 82.5.
=67.5°.
(3)

Deepak menaria said:   5 years ago
5:15 time.
5 hr angle = 5x30 = 150.
15 min in hour =(15/60)x30 =7.5.
150+7.5=157.5.

In minute hand for 15 min.
Minute hand angle is 6 degree so,
For 15 min = 15x6 =90.

So,
157.5 - 90 = 67.5 degree, Answer.
(5)

Santosh said:   9 years ago
Answer is very simple.

Difference between the hour hand and minute hand is 60 deg but for every minute hour hand will move by 1/2deg and for 15 min hour hand is moved by 7.5 deg so total is 60+7.5 = 67.5 deg.

Hema sri said:   9 years ago
They given what angle hands of a clock k 5hrs 15min.

Actually 60min = 30degree.
1min = 1/2degree.

So what is the degree of 15min?

So 15/2 = 7.5.

We add 60min in 7.5 degrees.

Then, the answer is 67.5.


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