Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 9 of 10.
Jagadish said:
8 years ago
How can I find 40 years & how many odd days?
Poonam said:
8 years ago
Please tell me why always take 1600 and 400?
Bidhya chhetri said:
9 years ago
Total odd day 0 + 0 + 4 + 3 = 7 = 0 Odd day.
Lakshmi said:
8 years ago
Why we take 1600 and 400 explain in detail?
Sumit said:
1 decade ago
11 odd days= 4 odd days. Can't understand.
Himanshu said:
7 years ago
How 2 Leap Year? Please Explain in detail.
Sonam Wangchuk said:
5 years ago
227 =3 odd days How? Actually 227/7 =4.
(4)
Pankaj Shelke said:
3 years ago
I think the correct answer is Friday.
(16)
Vaishnavi said:
6 years ago
On what basis is m being determined?
Saurav said:
1 decade ago
How 1600 and 400 gets 0 odd days ?
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