Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Sunday
Monday
Tuesday
Friday
Answer: Option
Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

Discussion:
95 comments Page 1 of 10.

Sudhakar N said:   7 months ago
= 1600 + 400 + 9 + (jan+feb+mar+apr+may+jun+jul) + 15 days,
= 0 + 0 + ((2*2) + (7*1)) + (3+0+3+2+3+2+3) + 15 days,
= (4+7) + 16 + 15,
= 11 + 31,
= 42.

To find odd days?
= 42/7 = 6 weeks and 0(zero odd days)
Odd days:
0 -> sunday
1 = Mon,
2 = Tue,
3 = Wen,
4 = Thu,
5 = Fri,
6 = Sat.
0 = 7 = Sun.

So, Sunday is the answer.
(4)

Mwesigwa Johnson said:   2 years ago
227รท7 = 32.42.

The remainder is 4 days, how are you guys getting 3 days?

Anyone, please explain to me.
(9)

Anonymous said:   2 years ago
The total odd days in 1600 years = 0
similarly total odd days in 400 years = 0.

So total odd days in 2000 years = 0,
after 2000 we have completed 9 years.

In those 9 years, in those 9 years, we have 2 leap years and 7 ordinary years
In a leap year, we have 366 days i.e. 52 weeks and 2 days = 2 odd days
In an ordinary year, we have 365 days i.e. 52 weeks and 1 day = 1 odd day.

So in 9 years = 2*2 + 7*1 = 11 in this 11 we have 1 week + 4 days = 4 odd days.

After those 9 years, the 10th year starts in that year we have Jan, Feb, Mar, Apr, May, Jun, Jul and 15 days of Aug.
So total days = 31+28+31+30+31+30+31+15=227 days = 32 weeks + 3 days=3 odd days.
So total odd days = 3+4=7 odd days = 1 week = 0 odd days.
0=7=Sun,
1=Mon,
2=Tue,
3=Wen,
4=Thu,
5=Fri,
6=Sat.
So, the given day is Sunday.
(14)

Vedant said:   3 years ago
Why do we consider only 9 Years, not 2 or 3?

Please explain me.
(3)

Pankaj Shelke said:   3 years ago
I think the correct answer is Friday.
(16)

Naman Parashar said:   3 years ago
If you divide eery month by "7" I.E.
JAN = 31/7 R = 3
SIMILARLY
JAN = 3
FEB = 0
MARCH = 3
APRIL = 2
MAY = 3
JUNE = 2
JULY = 3
AUGUST = 15 (BECAUSE NO. OF DAYS COMPLETED )
SO, THE SUM IS;
3+0+3+2+3+2+3+15 = 31.

NOW DIVIDE 31/7, R = 3.
0 = SUNDAY
1 = MONDAY
2 = TUESDAY
3 = WEDNESDAY
4 = THURSDAY
5 = FRIDAY
6 = SATURDAY
7 = SUNDAY (= 0)

Then, R = 3.

Then the answer would be " WEDNESDAY".
(13)

Joseph said:   4 years ago
Why is it that the year's code is varying? Sometimes Jan is given code as 1, Feb as 4, Mar 4 April 0 and so on and again in another instance you find Jan given code 0, feb as 3 Mar 3 April 6, may 2. What brings the variation?

Anyone, please explain.
(2)

Aayush said:   4 years ago
Why Everyone is saying"As Odd days = 0 day is Sunday".

The odd day is Zero from 1 Jan- Monday.

So isn't the answer should be Monday? Please clarify this.
(10)

Adithya said:   5 years ago
Why 9 years? Is'nt it 10 years?

Sonam Wangchuk said:   5 years ago
227 =3 odd days How? Actually 227/7 =4.
(4)


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