Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Sunday
Monday
Tuesday
Friday
Answer: Option
Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

Discussion:
95 comments Page 1 of 10.

Sumit said:   1 decade ago
11 odd days= 4 odd days. Can't understand.

Hary said:   1 decade ago
Sumit,

11 days are left and in those 11 days,week days (7) are subtracted so the remaining are 11-7=4 odd days.

Saurav said:   1 decade ago
How 1600 and 400 gets 0 odd days ?

Boney said:   1 decade ago
If we divide 1600/400 we will get zero as remainder so it has zero odd days.
so in 2000 yrs we have 0 odd days.
In 9 yrs there r 2 leap years
leap yrs have 2 odd days(366/7 2 as remainder) and
non leapyr have 1 odd day totaling we have 2*2+7*1=11 odd days
Now cal no: of days in 2010 upto aug 15 then dividing by 7
will give no of odd days 2010 which is 3.

Rashi said:   1 decade ago
Thanks boney.

John said:   1 decade ago
Why we are taking the 2000 years as 1600 and 400 years ?

Sundar said:   1 decade ago
@John

You can find the answer for your question in this page.

http://www.indiabix.com/aptitude/calendar/discussion-638

Hope this help you. Have a nice day!

Rakesh said:   1 decade ago
How can I know 9years has (2leap + 7 nonleap)?

Rupali said:   1 decade ago
Please can you tell me how you write the.

Total number of odd days = (0 + 0 + 4 + 3) = 7 odd days.

I can't understand this step.

Trilochan said:   1 decade ago
@Rupali: First you go through the Important formluas which is given in the 1st page .


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