Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 10 of 10.
Pankaj Shelke said:
3 years ago
I think the correct answer is Friday.
(16)
Vedant said:
3 years ago
Why do we consider only 9 Years, not 2 or 3?
Please explain me.
Please explain me.
(3)
Anonymous said:
2 years ago
The total odd days in 1600 years = 0
similarly total odd days in 400 years = 0.
So total odd days in 2000 years = 0,
after 2000 we have completed 9 years.
In those 9 years, in those 9 years, we have 2 leap years and 7 ordinary years
In a leap year, we have 366 days i.e. 52 weeks and 2 days = 2 odd days
In an ordinary year, we have 365 days i.e. 52 weeks and 1 day = 1 odd day.
So in 9 years = 2*2 + 7*1 = 11 in this 11 we have 1 week + 4 days = 4 odd days.
After those 9 years, the 10th year starts in that year we have Jan, Feb, Mar, Apr, May, Jun, Jul and 15 days of Aug.
So total days = 31+28+31+30+31+30+31+15=227 days = 32 weeks + 3 days=3 odd days.
So total odd days = 3+4=7 odd days = 1 week = 0 odd days.
0=7=Sun,
1=Mon,
2=Tue,
3=Wen,
4=Thu,
5=Fri,
6=Sat.
So, the given day is Sunday.
similarly total odd days in 400 years = 0.
So total odd days in 2000 years = 0,
after 2000 we have completed 9 years.
In those 9 years, in those 9 years, we have 2 leap years and 7 ordinary years
In a leap year, we have 366 days i.e. 52 weeks and 2 days = 2 odd days
In an ordinary year, we have 365 days i.e. 52 weeks and 1 day = 1 odd day.
So in 9 years = 2*2 + 7*1 = 11 in this 11 we have 1 week + 4 days = 4 odd days.
After those 9 years, the 10th year starts in that year we have Jan, Feb, Mar, Apr, May, Jun, Jul and 15 days of Aug.
So total days = 31+28+31+30+31+30+31+15=227 days = 32 weeks + 3 days=3 odd days.
So total odd days = 3+4=7 odd days = 1 week = 0 odd days.
0=7=Sun,
1=Mon,
2=Tue,
3=Wen,
4=Thu,
5=Fri,
6=Sat.
So, the given day is Sunday.
(14)
Mwesigwa Johnson said:
2 years ago
227รท7 = 32.42.
The remainder is 4 days, how are you guys getting 3 days?
Anyone, please explain to me.
The remainder is 4 days, how are you guys getting 3 days?
Anyone, please explain to me.
(9)
Sudhakar N said:
7 months ago
= 1600 + 400 + 9 + (jan+feb+mar+apr+may+jun+jul) + 15 days,
= 0 + 0 + ((2*2) + (7*1)) + (3+0+3+2+3+2+3) + 15 days,
= (4+7) + 16 + 15,
= 11 + 31,
= 42.
To find odd days?
= 42/7 = 6 weeks and 0(zero odd days)
Odd days:
0 -> sunday
1 = Mon,
2 = Tue,
3 = Wen,
4 = Thu,
5 = Fri,
6 = Sat.
0 = 7 = Sun.
So, Sunday is the answer.
= 0 + 0 + ((2*2) + (7*1)) + (3+0+3+2+3+2+3) + 15 days,
= (4+7) + 16 + 15,
= 11 + 31,
= 42.
To find odd days?
= 42/7 = 6 weeks and 0(zero odd days)
Odd days:
0 -> sunday
1 = Mon,
2 = Tue,
3 = Wen,
4 = Thu,
5 = Fri,
6 = Sat.
0 = 7 = Sun.
So, Sunday is the answer.
(4)
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