Aptitude - Calendar - Discussion

(15+10+2+6+10/4)= 35/7 = 0.

@Madhu.

For 15 years we have 3 leap year (12/4=3).
And 12 ordinary years,
So total num of odd days=(3*2+12*1)=18,

(Add 2 point for leap year because 2 days will shift for the next year odd days is the actual concept that if 2016 Jan 1 is sunday then 2017 Jan would be Monday but after a leap year it would be Tuesday so 2 days will shift).

And try to divide the number of odd days with 7.

Here it is 18 cant divide by 7.
So 14/7=2.
Then 4 days are remaining then 4 is the num of odd days.
*(dividing 7 means a week have seven days).

We have an easy method.

Follow this if you feel it simple.

This is a easy code technique.

Year cheat code, Month cheat code, and date cheat code are the three types.

YEAR CHEAT CODE:

1600 to 1699 = 6.
1700 to 1799 = 4.
1800 to 1899 = 2.
1900 to 1999 = 0.
2000 to 2010 = 6.

MONTH CHEAT CODE:

Jan = 0.
Feb = 3.
Mar = 3.
Apr = 6.
May = 1.
Jun = 4.
Jul = 6.
Aug = 2.
Sep = 5.
Oct = 0.
Nov = 3.
Dec = 5.

DAY CHEAT CODE:

Sunday = 0.
Monday = 1.
Tuesday = 2.
Wednesday = 3.
Thursday = 4.
Friday = 5.
Saturday = 6.

Now, let's take an example,

11/03/1997 which is my birthday.

Step 1: Take the last two digits of the year = 97.

Step 2: Take the date = 11.

Step 3: Divide 97 by 4 and take the quotient = 24.

Step 4: Take the year cheat code = 0 (For the range 1900 to 1997).

Step 5: Take the Month cheat code = 03.

Now add all the results.

97+11+24+00+03 = 135.

Divide the answer by 7 and consider the remainder = 2 (Subtract 1 from this in case of a leap year).

Which is the Cheat code for Tuesday, therefore the answer is Tuesday.

@John. 2000 is splint into a possible and nearest 4th century to the figure and after a remainder is obtained.

i.e 2000 = 1600 + 400.

We can get a number of odd days in 9years by dividing 9 by 4 as in every 4 years there is a leap year. The quotient is the number of leap years and rest is ordinary years so,

9years = 2leap years + 7ordinary years.

227 =3 odd days How? Actually 227/7 =4.

Why 9 years? Is'nt it 10 years?

Why Everyone is saying"As Odd days = 0 day is Sunday".

The odd day is Zero from 1 Jan- Monday.

So isn't the answer should be Monday? Please clarify this.

Why is it that the year's code is varying? Sometimes Jan is given code as 1, Feb as 4, Mar 4 April 0 and so on and again in another instance you find Jan given code 0, feb as 3 Mar 3 April 6, may 2. What brings the variation?

Anyone, please explain.

If you divide eery month by "7" I.E.
JAN = 31/7 R = 3
SIMILARLY
JAN = 3
FEB = 0
MARCH = 3
APRIL = 2
MAY = 3
JUNE = 2
JULY = 3
AUGUST = 15 (BECAUSE NO. OF DAYS COMPLETED )
SO, THE SUM IS;
3+0+3+2+3+2+3+15 = 31.

NOW DIVIDE 31/7, R = 3.
0 = SUNDAY
1 = MONDAY
2 = TUESDAY
3 = WEDNESDAY
4 = THURSDAY
5 = FRIDAY
6 = SATURDAY
7 = SUNDAY (= 0)

Then, R = 3.

Then the answer would be " WEDNESDAY".