Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Sunday
Monday
Tuesday
Friday
Answer: Option
Explanation:

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan.  Feb.   March    April    May  June  July  Aug. 
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

Discussion:
95 comments Page 8 of 10.

Priya said:   8 years ago
@Poonam.

1600 & 400 are reference years with which we calculate the solution. As they leave 0 odd days. So we can calculate fresh.

Pramod said:   7 years ago
2+(10/12)+rem(10/12)+(rem(10/12)/4).
2+0+10+2 = 14.

Komal said:   7 years ago
I have a question.

How in 100 years, 76 was ordinary years and 24 was leap years?

Because generally, every 4 year is a leap year, so 100 is completely divisible by 4 and we get 25, so in general, in 100 years, there were 25 leap years?

Please, anyone, explain this to me.

Himanshu said:   7 years ago
How 2 Leap Year? Please Explain in detail.

Biswas said:   7 years ago
@All.

It is simple, zero refers to Sunday in calendar rule, Monday = 1, same as if the total number of odd days is 6 it's your Saturday.

Saipreethi said:   7 years ago
How can I find, if they have given the years in 1500 and 1600? Please explain.

Thinlay Penjor said:   7 years ago
Hello.

Why we are taking the odd number of 1600 years, 400 years and 9 years when it is only asked any the day on 15th August 2010?

Madhu said:   7 years ago
How many odd days in 15 years? please tell me the answer.

Muzige said:   6 years ago
@Vaibhav.

In the formula f = k + (13m-1)/5 +d + (d/4)+(c/4)-2c, how to determine m?

Vaishnavi said:   6 years ago
On what basis is m being determined?


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