Aptitude - Calendar - Discussion

I think the correct answer is Friday.

The total odd days in 1600 years = 0
similarly total odd days in 400 years = 0.

So total odd days in 2000 years = 0,
after 2000 we have completed 9 years.

In those 9 years, in those 9 years, we have 2 leap years and 7 ordinary years
In a leap year, we have 366 days i.e. 52 weeks and 2 days = 2 odd days
In an ordinary year, we have 365 days i.e. 52 weeks and 1 day = 1 odd day.

So in 9 years = 2*2 + 7*1 = 11 in this 11 we have 1 week + 4 days = 4 odd days.

After those 9 years, the 10th year starts in that year we have Jan, Feb, Mar, Apr, May, Jun, Jul and 15 days of Aug.
So total days = 31+28+31+30+31+30+31+15=227 days = 32 weeks + 3 days=3 odd days.
So total odd days = 3+4=7 odd days = 1 week = 0 odd days.
0=7=Sun,
1=Mon,
2=Tue,
3=Wen,
4=Thu,
5=Fri,
6=Sat.
So, the given day is Sunday.

If you divide eery month by "7" I.E.
JAN = 31/7 R = 3
SIMILARLY
JAN = 3
FEB = 0
MARCH = 3
APRIL = 2
MAY = 3
JUNE = 2
JULY = 3
AUGUST = 15 (BECAUSE NO. OF DAYS COMPLETED )
SO, THE SUM IS;
3+0+3+2+3+2+3+15 = 31.

NOW DIVIDE 31/7, R = 3.
0 = SUNDAY
1 = MONDAY
2 = TUESDAY
3 = WEDNESDAY
4 = THURSDAY
5 = FRIDAY
6 = SATURDAY
7 = SUNDAY (= 0)

Then, R = 3.

Then the answer would be " WEDNESDAY".

Why Everyone is saying"As Odd days = 0 day is Sunday".

The odd day is Zero from 1 Jan- Monday.

So isn't the answer should be Monday? Please clarify this.

227÷7 = 32.42.

The remainder is 4 days, how are you guys getting 3 days?

Anyone, please explain to me.

= 1600 + 400 + 9 + (jan+feb+mar+apr+may+jun+jul) + 15 days,
= 0 + 0 + ((2*2) + (7*1)) + (3+0+3+2+3+2+3) + 15 days,
= (4+7) + 16 + 15,
= 11 + 31,
= 42.

To find odd days?
= 42/7 = 6 weeks and 0(zero odd days)
Odd days:
0 -> sunday
1 = Mon,
2 = Tue,
3 = Wen,
4 = Thu,
5 = Fri,
6 = Sat.
0 = 7 = Sun.

So, Sunday is the answer.

We have an easy method.

Follow this if you feel it simple.

This is a easy code technique.

Year cheat code, Month cheat code, and date cheat code are the three types.

YEAR CHEAT CODE:

1600 to 1699 = 6.
1700 to 1799 = 4.
1800 to 1899 = 2.
1900 to 1999 = 0.
2000 to 2010 = 6.

MONTH CHEAT CODE:

Jan = 0.
Feb = 3.
Mar = 3.
Apr = 6.
May = 1.
Jun = 4.
Jul = 6.
Aug = 2.
Sep = 5.
Oct = 0.
Nov = 3.
Dec = 5.

DAY CHEAT CODE:

Sunday = 0.
Monday = 1.
Tuesday = 2.
Wednesday = 3.
Thursday = 4.
Friday = 5.
Saturday = 6.

Now, let's take an example,

11/03/1997 which is my birthday.

Step 1: Take the last two digits of the year = 97.

Step 2: Take the date = 11.

Step 3: Divide 97 by 4 and take the quotient = 24.

Step 4: Take the year cheat code = 0 (For the range 1900 to 1997).

Step 5: Take the Month cheat code = 03.

Now add all the results.

97+11+24+00+03 = 135.

Divide the answer by 7 and consider the remainder = 2 (Subtract 1 from this in case of a leap year).

Which is the Cheat code for Tuesday, therefore the answer is Tuesday.

227 =3 odd days How? Actually 227/7 =4.

Why do we consider only 9 Years, not 2 or 3?

Please explain me.

Why is it that the year's code is varying? Sometimes Jan is given code as 1, Feb as 4, Mar 4 April 0 and so on and again in another instance you find Jan given code 0, feb as 3 Mar 3 April 6, may 2. What brings the variation?

Anyone, please explain.