Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 2 of 10.
Aditya said:
5 years ago
We can get a number of odd days in 9years by dividing 9 by 4 as in every 4 years there is a leap year. The quotient is the number of leap years and rest is ordinary years so,
9years = 2leap years + 7ordinary years.
9years = 2leap years + 7ordinary years.
Habib said:
5 years ago
@John. 2000 is splint into a possible and nearest 4th century to the figure and after a remainder is obtained.
i.e 2000 = 1600 + 400.
i.e 2000 = 1600 + 400.
Uiyutvbjh said:
5 years ago
We have an easy method.
Follow this if you feel it simple.
This is a easy code technique.
Year cheat code, Month cheat code, and date cheat code are the three types.
YEAR CHEAT CODE:
1600 to 1699 = 6.
1700 to 1799 = 4.
1800 to 1899 = 2.
1900 to 1999 = 0.
2000 to 2010 = 6.
MONTH CHEAT CODE:
Jan = 0.
Feb = 3.
Mar = 3.
Apr = 6.
May = 1.
Jun = 4.
Jul = 6.
Aug = 2.
Sep = 5.
Oct = 0.
Nov = 3.
Dec = 5.
DAY CHEAT CODE:
Sunday = 0.
Monday = 1.
Tuesday = 2.
Wednesday = 3.
Thursday = 4.
Friday = 5.
Saturday = 6.
Now, let's take an example,
11/03/1997 which is my birthday.
Step 1: Take the last two digits of the year = 97.
Step 2: Take the date = 11.
Step 3: Divide 97 by 4 and take the quotient = 24.
Step 4: Take the year cheat code = 0 (For the range 1900 to 1997).
Step 5: Take the Month cheat code = 03.
Now add all the results.
97+11+24+00+03 = 135.
Divide the answer by 7 and consider the remainder = 2 (Subtract 1 from this in case of a leap year).
Which is the Cheat code for Tuesday, therefore the answer is Tuesday.
Follow this if you feel it simple.
This is a easy code technique.
Year cheat code, Month cheat code, and date cheat code are the three types.
YEAR CHEAT CODE:
1600 to 1699 = 6.
1700 to 1799 = 4.
1800 to 1899 = 2.
1900 to 1999 = 0.
2000 to 2010 = 6.
MONTH CHEAT CODE:
Jan = 0.
Feb = 3.
Mar = 3.
Apr = 6.
May = 1.
Jun = 4.
Jul = 6.
Aug = 2.
Sep = 5.
Oct = 0.
Nov = 3.
Dec = 5.
DAY CHEAT CODE:
Sunday = 0.
Monday = 1.
Tuesday = 2.
Wednesday = 3.
Thursday = 4.
Friday = 5.
Saturday = 6.
Now, let's take an example,
11/03/1997 which is my birthday.
Step 1: Take the last two digits of the year = 97.
Step 2: Take the date = 11.
Step 3: Divide 97 by 4 and take the quotient = 24.
Step 4: Take the year cheat code = 0 (For the range 1900 to 1997).
Step 5: Take the Month cheat code = 03.
Now add all the results.
97+11+24+00+03 = 135.
Divide the answer by 7 and consider the remainder = 2 (Subtract 1 from this in case of a leap year).
Which is the Cheat code for Tuesday, therefore the answer is Tuesday.
(4)
Nithin paul said:
6 years ago
@Madhu.
For 15 years we have 3 leap year (12/4=3).
And 12 ordinary years,
So total num of odd days=(3*2+12*1)=18,
(Add 2 point for leap year because 2 days will shift for the next year odd days is the actual concept that if 2016 Jan 1 is sunday then 2017 Jan would be Monday but after a leap year it would be Tuesday so 2 days will shift).
And try to divide the number of odd days with 7.
Here it is 18 cant divide by 7.
So 14/7=2.
Then 4 days are remaining then 4 is the num of odd days.
*(dividing 7 means a week have seven days).
For 15 years we have 3 leap year (12/4=3).
And 12 ordinary years,
So total num of odd days=(3*2+12*1)=18,
(Add 2 point for leap year because 2 days will shift for the next year odd days is the actual concept that if 2016 Jan 1 is sunday then 2017 Jan would be Monday but after a leap year it would be Tuesday so 2 days will shift).
And try to divide the number of odd days with 7.
Here it is 18 cant divide by 7.
So 14/7=2.
Then 4 days are remaining then 4 is the num of odd days.
*(dividing 7 means a week have seven days).
THIRU said:
6 years ago
(15+10+2+6+10/4)= 35/7 = 0.
Vaishnavi said:
6 years ago
On what basis is m being determined?
Muzige said:
6 years ago
@Vaibhav.
In the formula f = k + (13m-1)/5 +d + (d/4)+(c/4)-2c, how to determine m?
In the formula f = k + (13m-1)/5 +d + (d/4)+(c/4)-2c, how to determine m?
Madhu said:
7 years ago
How many odd days in 15 years? please tell me the answer.
Thinlay Penjor said:
7 years ago
Hello.
Why we are taking the odd number of 1600 years, 400 years and 9 years when it is only asked any the day on 15th August 2010?
Why we are taking the odd number of 1600 years, 400 years and 9 years when it is only asked any the day on 15th August 2010?
Saipreethi said:
7 years ago
How can I find, if they have given the years in 1500 and 1600? Please explain.
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