Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 10 of 10.
Rashi said:
1 decade ago
Thanks boney.
Boney said:
1 decade ago
If we divide 1600/400 we will get zero as remainder so it has zero odd days.
so in 2000 yrs we have 0 odd days.
In 9 yrs there r 2 leap years
leap yrs have 2 odd days(366/7 2 as remainder) and
non leapyr have 1 odd day totaling we have 2*2+7*1=11 odd days
Now cal no: of days in 2010 upto aug 15 then dividing by 7
will give no of odd days 2010 which is 3.
so in 2000 yrs we have 0 odd days.
In 9 yrs there r 2 leap years
leap yrs have 2 odd days(366/7 2 as remainder) and
non leapyr have 1 odd day totaling we have 2*2+7*1=11 odd days
Now cal no: of days in 2010 upto aug 15 then dividing by 7
will give no of odd days 2010 which is 3.
Saurav said:
1 decade ago
How 1600 and 400 gets 0 odd days ?
Hary said:
1 decade ago
Sumit,
11 days are left and in those 11 days,week days (7) are subtracted so the remaining are 11-7=4 odd days.
11 days are left and in those 11 days,week days (7) are subtracted so the remaining are 11-7=4 odd days.
Sumit said:
1 decade ago
11 odd days= 4 odd days. Can't understand.
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