Aptitude - Calendar - Discussion

Dear friends,

Pls. explain which day will come on 25th dec 1992 with step by step procedure

@vishnu : those 4 days are the result of 11days(divide these 11days into weeks and days, so u get 7+4,here 7days makes a week and do count those 4 extra days.) so finally we get 4ODD DAYS..

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

How com tat 4 odd days ?

How for march the value of month is 6? I don't understand the month value.

Hey, this type of questions can be easily done by following formula
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f= K+[(13m-1)/5]+ d+[d/4]+[c/4]-2c

Here k= date of which you have to calculate(15 in above que.)
m= month (for march, m=1 and so on..for jan m=11)
d= last two digit of given year(10 in above que.)
c= first two digit of given year(20 in above que.)
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note: take only integer value after division for ex. 13/5=2
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For given question

15th August, 2010?

f=15+[(13*6-1)/5]+10+[10/4]+[20/4]-2*20
=15+15+ 10 + 2 + 5 -40
=7

Now 7%7==0

So its SUNDAY.

@Rupali: First you go through the Important formluas which is given in the 1st page .

Please can you tell me how you write the.

Total number of odd days = (0 + 0 + 4 + 3) = 7 odd days.

I can't understand this step.

How can I know 9years has (2leap + 7 nonleap)?

@John

You can find the answer for your question in this page.

http://www.indiabix.com/aptitude/calendar/discussion-638

Hope this help you. Have a nice day!

Why we are taking the 2000 years as 1600 and 400 years ?