Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 8 of 10.
Nagu said:
1 decade ago
How can I know 9 years = (7 ordinary years +2 leap years).
Kiran said:
1 decade ago
Please explain how
Total no of odd days = (0+0+4+3) = 7?
Total no of odd days = (0+0+4+3) = 7?
Madhu said:
7 years ago
How many odd days in 15 years? please tell me the answer.
John said:
1 decade ago
Why we are taking the 2000 years as 1600 and 400 years ?
Pramod said:
7 years ago
2+(10/12)+rem(10/12)+(rem(10/12)/4).
2+0+10+2 = 14.
2+0+10+2 = 14.
Nagaraju said:
1 decade ago
Friends can you explain 7%7=0 taken as sunday how?
Candy said:
9 years ago
I am not understand please say how will it come?
Raunak Thakur said:
9 years ago
How 100 years has 24 leap years? Please explain.
Maheshwaree said:
10 years ago
How to find month code, day code and year code?
Rakesh said:
1 decade ago
How can I know 9years has (2leap + 7 nonleap)?
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