Aptitude - Calendar - Discussion

How to find month code, day code and year code?

So each year has one odd day and leap year has 2 odd days for every 100 years 100+24 odd days but after every 7 days the same day repeats for example today is Saturday after 7 days will be Saturday basing on this we neglect multiples of 7 and by dividing 124 with 7 we get 5 odd days.

So 100 years have 5 odd days but for every 400 years one day is added based on earth's rotation don't ask me about that so 400 years have 20+1 odd days which means 3 weeks and can be neglected as same day appears after any number of complete weeks.

1 year means 365 days it has one odd day after divide with 7 so if this year starts with Sunday then next year starts with Monday but if this year is leap year that means a multiple of 4 then next year starts with Tuesday.

Let me make it clear 0 means Sunday 1 means Monday 2 means Tuesday 3 means Wednesday 4 means Thursday 5 means Friday 6 means Saturday 7 means 0 in terms of odd days.

How you take 1600 and 400? I can't understand please tell me.

Is anyone have the simplest way to give answer to this question? How can we understand the year said is leap year?

I can't understand please anyone understand me in easy language.

We have 365 days for normal year, 366 days for leap year. So how no of odd days in 400 years is '0'.

Given that 15th august, 2010.

1) Add day and last two digits of the year 15+10 = 25.

2) Divide last two digit of the year by 4, so 10/4 = 2.

3) Add quotient value to step 1.

= 25+2+2(month code)+6(year code) = 35.

4) Divide 35/7 = 5 it means remainder is 0(day code) Sunday.

Please explain 24-2-2015; Above date is what day of the week;