Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 4)
4.
What will be the day of the week 15th August, 2010?
Answer: Option
Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 
4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.
Discussion:
95 comments Page 5 of 10.
Bidhya said:
9 years ago
Please help me to understand. Why a total number of odd days = 0 + 0 + 4 + 3 = 7.
Bidhya chhetri said:
9 years ago
Total odd day 0 + 0 + 4 + 3 = 7 = 0 Odd day.
Keisha said:
9 years ago
15 th August 2010.
Jan 31 + feb 28 + Mar 31 + Apr 30 + May 31 + June 30 + July 31+ Aug 15.
31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227.
227/7 = 3 odd days.
*************************************.
For 10 years.
2000 + 2001 + 2002 + 2003 + 2004 + 2005 + 2006 + 2007 + 2008 + 2009.
(In 400, 1600, 2000 odd days are zero. ).
0 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 (odd days).
= 11 odd days.
Total odd days = 3 + 11 = 14.
14/7= 7.
We have 2 leap year + 7 ordinary years so =2 * 2 + 7 = 4 + 7 = 11 = 4 odd days
So, 4 + 3 = 7.
7/7 = 0 = Sunday.
Jan 31 + feb 28 + Mar 31 + Apr 30 + May 31 + June 30 + July 31+ Aug 15.
31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 227.
227/7 = 3 odd days.
*************************************.
For 10 years.
2000 + 2001 + 2002 + 2003 + 2004 + 2005 + 2006 + 2007 + 2008 + 2009.
(In 400, 1600, 2000 odd days are zero. ).
0 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 (odd days).
= 11 odd days.
Total odd days = 3 + 11 = 14.
14/7= 7.
We have 2 leap year + 7 ordinary years so =2 * 2 + 7 = 4 + 7 = 11 = 4 odd days
So, 4 + 3 = 7.
7/7 = 0 = Sunday.
(1)
Keisha said:
9 years ago
How do we know if we have to take for 5 years or for 10 years?
Raunak Thakur said:
9 years ago
How 100 years has 24 leap years? Please explain.
Candy said:
9 years ago
I am not understand please say how will it come?
Vani said:
10 years ago
Instead of taking 2000 as reference can we take 2008 as it is also a leap year and closer to 2009?
DATTA said:
10 years ago
2000 to 2010 having 10 years.
In which 3 leap year (2000-01), (2004-05), (2008-09) & 7 normal years.
3 leap years have 6 odd days (3 years * 2 odd days) = 6 odd day.
Remaining 7 year having 7 odd day (individually 1) & for year (2010-11).
January February March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days.
No of odd day = 227/7 = Remainder is 3.
So total odd days are 3+6+7 = 16.
Now 16/7, remainder is 2.
So Tuesday will come.
So how answer will come (Sunday)?
In which 3 leap year (2000-01), (2004-05), (2008-09) & 7 normal years.
3 leap years have 6 odd days (3 years * 2 odd days) = 6 odd day.
Remaining 7 year having 7 odd day (individually 1) & for year (2010-11).
January February March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days.
No of odd day = 227/7 = Remainder is 3.
So total odd days are 3+6+7 = 16.
Now 16/7, remainder is 2.
So Tuesday will come.
So how answer will come (Sunday)?
Saikumar said:
10 years ago
1600 = 0 odd days.
400 years = 0 odd days.
15 years will be remained.
15 year will have (3 leap years + 12 ordinary years).
= (3*2+1*12) = (6+12) = 18 = 7+7+4 = 4 odd days.
8 = 1 week+1 day.
(0+0+4+1) = 5 days = Friday.
400 years = 0 odd days.
15 years will be remained.
15 year will have (3 leap years + 12 ordinary years).
= (3*2+1*12) = (6+12) = 18 = 7+7+4 = 4 odd days.
8 = 1 week+1 day.
(0+0+4+1) = 5 days = Friday.
Venkat said:
10 years ago
What is the day on 8th January 2015 please explain briefly?
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