Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 6)
6.
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Answer: Option
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Discussion:
111 comments Page 5 of 12.
Mou said:
7 years ago
I guess it should be Saturday, as 2004 March is after Feb, so Feb gets automatically calculated while considering March, 2004 being the leap year, every day gets moved to another +1, thus 2005 March 6th should be a Saturday, (in total +2) logically, and based on calculation as well it gives Saturday.
Am I right?
Am I right?
Vamsi said:
7 years ago
According to me, the actual answer is Saturday.
Anshul Gupta said:
7 years ago
1600 years ---> 0 odd days.
400 years -----> 0 odd days.
remaining 3 years ------> 3 ordinary years.
= 3 x 1 = 3 odd days.
Now 31(jan) + 29(feb leap year) + 6(march) = 66 days = 9 weeks and 3 odd days.
So, the total odd days = 0 + 3 + 3 = 6 odd days = Saturday.
So Why not I'm getting the given answer. Please clarify for me.
400 years -----> 0 odd days.
remaining 3 years ------> 3 ordinary years.
= 3 x 1 = 3 odd days.
Now 31(jan) + 29(feb leap year) + 6(march) = 66 days = 9 weeks and 3 odd days.
So, the total odd days = 0 + 3 + 3 = 6 odd days = Saturday.
So Why not I'm getting the given answer. Please clarify for me.
Ganesh said:
7 years ago
I think the answer should be Sunday.
Deyo said:
7 years ago
Why Feb is not included?
Ravi said:
8 years ago
Step1: No.of odd days 2000=0.
Step2: No.of odd days 400=0.
Step3: No.of odd days (2001-2003)=3.
Step4: No.of odd days (Jan=31+Feb=29+march=6)=66-(9 weeks+3 days)=3. Total No.of odd days=0+0+3+3=6.
Monday=1.
6+1=7. Is 0 answer is Sunday.
Step2: No.of odd days 400=0.
Step3: No.of odd days (2001-2003)=3.
Step4: No.of odd days (Jan=31+Feb=29+march=6)=66-(9 weeks+3 days)=3. Total No.of odd days=0+0+3+3=6.
Monday=1.
6+1=7. Is 0 answer is Sunday.
Nidhi said:
8 years ago
Sunday since they assumed 6th March 2005 as Monday and not Sunday so the day will be increased by 1 hence 1 + Saturday = Sunday.
Gipu said:
8 years ago
Saturday is correct.
Ravi Yadav said:
8 years ago
It will be Saturday.
Avinash Kumar (Hajipur) said:
8 years ago
Find 6 March 2004 what will the Day ?
So, 2004 we consider last two digit then 04 also than add in 100 ; 100+04=104 i.e 26.
Again we add 104+26(and given Month is March so a.c to this we can add 3) +03+(given date is 06);
FInally add: 104+26+03+06 = 139.
Again 139 is divided by 7;
So 139/7 remainder is 06.
Result is 0 is Sunday, 01 Mon, 02,Tues, 04 wed, 05 Thu; 06 sat;
So final ans is 06 (Saturday).
Thank You.
So, 2004 we consider last two digit then 04 also than add in 100 ; 100+04=104 i.e 26.
Again we add 104+26(and given Month is March so a.c to this we can add 3) +03+(given date is 06);
FInally add: 104+26+03+06 = 139.
Again 139 is divided by 7;
So 139/7 remainder is 06.
Result is 0 is Sunday, 01 Mon, 02,Tues, 04 wed, 05 Thu; 06 sat;
So final ans is 06 (Saturday).
Thank You.
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