Aptitude - Calendar - Discussion

The Correct answer is Saturday.

It should be a Saturday.
= (D+M+Y+LP)/7.
= (6+3+104+26)/7,
= 139/7.
= 6 that is Saturday.

@All.

Note : Their is "if" Written in question,
Means we need to assume that in
6th march, 2005 is Monday.


Points to remember:-
1)

5th march, 2004 --- 6th march 2005 is
Equivalent to 1 year.
Means starting day and ending day is
Same for basic year.
Thus;

5th march 2004=6th march 2005= Monday.
For basic year;
6th march 2004 = Monday -1= Sunday.
Here, 1 means one day back.

2) For leap year.
Monday-2

Read question carefully,
If it is written in question that 2000 is not a leap year,
Then we need to assume it.

Hope it will help you.

Saturday is the right answer.
Solution: 6 March 2004
cc+yc+mc+d.
6+5+3+6 = 20/7= 6 which is Saturday.

Agree, Saturday is the correct answer.

I think the correct answer is Saturday.

I think the Answer is Saturday.

I don't understand this. Please help me to get this.

This is an easy way to solve that all problems:

***********************************************
It is used to solve all problems. I have given below.

2004>>>is a leap year 366days ,feb-29-1 odd day
100 years>>> 5odd day.
200years>>>3 odd day.
300 years>>> 1odd day.
400 years>>> 0 odd day.

Month of total 31 days means>>>3 odd day.
Month of total 30 days means>>>2odd day.
Month of total 28 days means>>>0 odd day.
we go to solve that problem>>>>>>
********************************************************************

Solution:

6th march 2004
>>>>we seperated to add year.

1. 1600+400+3yr+(jan+feb)+6days.
|
400=0,4*400=1600,3yr we check how many leap year& ordinary year 3/4=not divisible So take 3 are odd.

2.0+0+3(1-odd)+(3+0)+6.
3.14 /7.
4.2 weeks 0 odd day.
5.we know 0 odd day is sunday.

So the answer is SUNDAY.

Thank You @Jagadish.

Your solution helped me to get the concept.