Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 6)
6.
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Answer: Option
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Discussion:
109 comments Page 2 of 11.
Evanjalin said:
3 years ago
It should be a Saturday.
= (D+M+Y+LP)/7.
= (6+3+104+26)/7,
= 139/7.
= 6 that is Saturday.
= (D+M+Y+LP)/7.
= (6+3+104+26)/7,
= 139/7.
= 6 that is Saturday.
(18)
Gautam dewasi said:
3 years ago
@All.
Note : Their is "if" Written in question,
Means we need to assume that in
6th march, 2005 is Monday.
Points to remember:-
1)
5th march, 2004 --- 6th march 2005 is
Equivalent to 1 year.
Means starting day and ending day is
Same for basic year.
Thus;
5th march 2004=6th march 2005= Monday.
For basic year;
6th march 2004 = Monday -1= Sunday.
Here, 1 means one day back.
2) For leap year.
Monday-2
Read question carefully,
If it is written in question that 2000 is not a leap year,
Then we need to assume it.
Hope it will help you.
Note : Their is "if" Written in question,
Means we need to assume that in
6th march, 2005 is Monday.
Points to remember:-
1)
5th march, 2004 --- 6th march 2005 is
Equivalent to 1 year.
Means starting day and ending day is
Same for basic year.
Thus;
5th march 2004=6th march 2005= Monday.
For basic year;
6th march 2004 = Monday -1= Sunday.
Here, 1 means one day back.
2) For leap year.
Monday-2
Read question carefully,
If it is written in question that 2000 is not a leap year,
Then we need to assume it.
Hope it will help you.
(14)
Veer said:
3 years ago
Saturday is the right answer.
Solution: 6 March 2004
cc+yc+mc+d.
6+5+3+6 = 20/7= 6 which is Saturday.
Solution: 6 March 2004
cc+yc+mc+d.
6+5+3+6 = 20/7= 6 which is Saturday.
(2)
Swapna said:
3 years ago
Agree, Saturday is the correct answer.
(2)
Chaithra said:
3 years ago
I think the correct answer is Saturday.
(1)
Praveen said:
3 years ago
I think the Answer is Saturday.
Jack said:
3 years ago
I don't understand this. Please help me to get this.
(1)
Prathap S said:
4 years ago
This is an easy way to solve that all problems:
***********************************************
It is used to solve all problems. I have given below.
2004>>>is a leap year 366days ,feb-29-1 odd day
100 years>>> 5odd day.
200years>>>3 odd day.
300 years>>> 1odd day.
400 years>>> 0 odd day.
Month of total 31 days means>>>3 odd day.
Month of total 30 days means>>>2odd day.
Month of total 28 days means>>>0 odd day.
we go to solve that problem>>>>>>
********************************************************************
Solution:
6th march 2004
>>>>we seperated to add year.
1. 1600+400+3yr+(jan+feb)+6days.
|
400=0,4*400=1600,3yr we check how many leap year& ordinary year 3/4=not divisible So take 3 are odd.
2.0+0+3(1-odd)+(3+0)+6.
3.14 /7.
4.2 weeks 0 odd day.
5.we know 0 odd day is sunday.
So the answer is SUNDAY.
***********************************************
It is used to solve all problems. I have given below.
2004>>>is a leap year 366days ,feb-29-1 odd day
100 years>>> 5odd day.
200years>>>3 odd day.
300 years>>> 1odd day.
400 years>>> 0 odd day.
Month of total 31 days means>>>3 odd day.
Month of total 30 days means>>>2odd day.
Month of total 28 days means>>>0 odd day.
we go to solve that problem>>>>>>
********************************************************************
Solution:
6th march 2004
>>>>we seperated to add year.
1. 1600+400+3yr+(jan+feb)+6days.
|
400=0,4*400=1600,3yr we check how many leap year& ordinary year 3/4=not divisible So take 3 are odd.
2.0+0+3(1-odd)+(3+0)+6.
3.14 /7.
4.2 weeks 0 odd day.
5.we know 0 odd day is sunday.
So the answer is SUNDAY.
(5)
Shania Balkhi said:
4 years ago
Thank You @Jagadish.
Your solution helped me to get the concept.
Your solution helped me to get the concept.
Nagaraja said:
4 years ago
There we need to follow 6 steps
1. Last two digits of the year in given is 04
2. Divide by 4 of the year is 01
3. Take the date in given is 06
4. Take the month in given is 03 (according to the formulas)
5. Take the year in given is 06.
(Add all the values - 04+01+06+03+06=20).
6. Divided by 7 of the values of 20 is 06
Here 06 is the value but we have one odd day in the year, let we add that the odd day in it is 06+01 = 07.
Hence the answer is 07 which means it is Sunday.
(*0 or 07 is same)
1. Last two digits of the year in given is 04
2. Divide by 4 of the year is 01
3. Take the date in given is 06
4. Take the month in given is 03 (according to the formulas)
5. Take the year in given is 06.
(Add all the values - 04+01+06+03+06=20).
6. Divided by 7 of the values of 20 is 06
Here 06 is the value but we have one odd day in the year, let we add that the odd day in it is 06+01 = 07.
Hence the answer is 07 which means it is Sunday.
(*0 or 07 is same)
(2)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers