Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 6)
6.
If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
Answer: Option
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
Discussion:
109 comments Page 11 of 11.
Shivansh said:
6 years ago
When we move from a leap year to a general year.
There is a increase of 2 days.
Similarly if 6 march 2005 was Monday then 6 march 2004 has to be Saturday.
There is a increase of 2 days.
Similarly if 6 march 2005 was Monday then 6 march 2004 has to be Saturday.
Dhivya Dharani said:
5 years ago
I don't have a clear idea about how to calculate the day for leap year by using simple tricks (ie) by using code for months.
Sohil said:
5 years ago
The correct answer is Saturday. Solve this by finding ordinary days upto 6th march 2004.
Anashitole said:
5 years ago
Saturday is the correct answer.
Ashwin said:
5 years ago
Since, March comes after Feb the one extra day in Feb will also get added. So, the correct answer is. Saturday.
Japhungshar said:
5 years ago
Isn't it Saturday right answer?
As from 6th March 2004 to 5th March 2005, we have one day. And 2 odd days till 6th March 2005. Which implies if 6th march 2004 is xth day then 5th march 2005 is (x+1)th day then comes 6th march which is (x+2)th day => if (x+2)th day is Monday then x is Saturday.
As from 6th March 2004 to 5th March 2005, we have one day. And 2 odd days till 6th March 2005. Which implies if 6th march 2004 is xth day then 5th march 2005 is (x+1)th day then comes 6th march which is (x+2)th day => if (x+2)th day is Monday then x is Saturday.
Saurabh Bhati said:
4 years ago
I think the answer is Saturday.
Because,
2000 = 0 odd day
2001 = 1 odd day
2002 = 1 odd day
2003 = 1 odd day.
Total (2001-2003) = 3 odd days.
2004 [Jan(31) + Feb(29) + Mar(06) = 66 days.
; 66/7 = 9 weeks 3 odd days.
Total odd days = 0 +3 + 3 = 6.
So, 6 is Saturday.
Because,
2000 = 0 odd day
2001 = 1 odd day
2002 = 1 odd day
2003 = 1 odd day.
Total (2001-2003) = 3 odd days.
2004 [Jan(31) + Feb(29) + Mar(06) = 66 days.
; 66/7 = 9 weeks 3 odd days.
Total odd days = 0 +3 + 3 = 6.
So, 6 is Saturday.
Shania Balkhi said:
4 years ago
Thank You @Jagadish.
Your solution helped me to get the concept.
Your solution helped me to get the concept.
Praveen said:
3 years ago
I think the Answer is Saturday.
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