Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
104 comments Page 6 of 11.
Rahul said:
1 decade ago
thanks ramya
Mahesh said:
1 decade ago
h+w+c/3 = 27.
h+w+c = 81.
w+c/2 = 20.
w+c = 40.
h+w+c = 81.
h+40 = 81.
h = 81-40.
h = 40.
h+w+c = 81.
w+c/2 = 20.
w+c = 40.
h+w+c = 81.
h+40 = 81.
h = 81-40.
h = 40.
Murali said:
1 decade ago
Given that average age of husband, wife, child 3 years ago was 27 years
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
Shah said:
1 decade ago
(3x27)+3 [ 27 is avg. age x 3 family members + 3( ie number years ago) ... Ans comes to 85 years.
(2x20)+5 [ 20 is avg. age of child and mother x 2 + 5( ie number years ago ... Ans comes to 45 years.
Now 85-45 = 40 years.
Is it correct way of solving ?
(2x20)+5 [ 20 is avg. age of child and mother x 2 + 5( ie number years ago ... Ans comes to 45 years.
Now 85-45 = 40 years.
Is it correct way of solving ?
Gopalkrishna said:
1 decade ago
Present age:
H+W+C=30*3.
W+C=25*2.
....................
ie...,H=40 year.
H+W+C=30*3.
W+C=25*2.
....................
ie...,H=40 year.
ALIYAZ said:
1 decade ago
@PRIYA.
[(h-3)+(w-3)+(c-3)/3] = 27.
[(h+w+c-9)/3] = 27.
[(h+w+c)/3]+(9/3) = 27.
[(h+w+c)/3] = 27+3 ====>h+w+c=30*3 ====>h+w+c=90.
Similarly w+c = 50.
[(h-3)+(w-3)+(c-3)/3] = 27.
[(h+w+c-9)/3] = 27.
[(h+w+c)/3]+(9/3) = 27.
[(h+w+c)/3] = 27+3 ====>h+w+c=30*3 ====>h+w+c=90.
Similarly w+c = 50.
Kholofelo said:
1 decade ago
What is algorithm?
Vijaykumar said:
1 decade ago
Good method to solve such type of question.
Raj said:
1 decade ago
No need to add 3 to all.
You have add 3 to avg it give avg age of all.
Then age of three number = 30*3 = 90.
Then add 5 to avg age of child and wife it gives present age i.e. 25.
Age of two persons = 25*2 = 50.
Age of husband = total age - two members age.
90 - 50 = 40.
You have add 3 to avg it give avg age of all.
Then age of three number = 30*3 = 90.
Then add 5 to avg age of child and wife it gives present age i.e. 25.
Age of two persons = 25*2 = 50.
Age of husband = total age - two members age.
90 - 50 = 40.
Ritu Sehgal said:
1 decade ago
Let husband present age - x.
Let wife present age - y.
Let son present age - z.
The average age of husband, wife and son before 3 years was 27.
i.e Before 3 year (x-3)+(y-3)+(z-3)/3 = 27.
x-3+y-3+z-3 = 27*3.
x+y+z = 81+9.
x+y+z = 90.....(1).
The average age of wife and son before 5 years was 20.
i.e Before 5 years (y-5)+(z-5)/2 = 20.
y-5+z-5 = 20*2.
y+z = 40+10.
y+z = 50....(2).
Now by subtracting equation 2 from equation 1, we will find x = 40.
Let wife present age - y.
Let son present age - z.
The average age of husband, wife and son before 3 years was 27.
i.e Before 3 year (x-3)+(y-3)+(z-3)/3 = 27.
x-3+y-3+z-3 = 27*3.
x+y+z = 81+9.
x+y+z = 90.....(1).
The average age of wife and son before 5 years was 20.
i.e Before 5 years (y-5)+(z-5)/2 = 20.
y-5+z-5 = 20*2.
y+z = 40+10.
y+z = 50....(2).
Now by subtracting equation 2 from equation 1, we will find x = 40.
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