Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
102 comments Page 1 of 11.
PRASHANTH JAVALI said:
1 month ago
As per statement.
SCENARIO 1 :
The average age of husband, wife and their child - 3 years ago was 27 years.
3 yrs ago was 27 means now = 30 (27+3),
therefore AVERAGE AGE =(H+W+C)/3=30,
By simplifying equation : (H+W+C)=90.
SCENARIO 2:
Wife and the child 5 years ago was 20 years
5YRS ago means now = 25 (20+5).
therefore average = (W+C)/2=25.
By simplifying equation : (W+C)=50.
W=50-C.
Now considering and subtituting in
SCENARIO 1# i.e
(H+W+C) = 90,
H+50-C+C = 90,
H+50 = 90,
H = 90-50,
H = 40.
HENCE B=40 IS The answer.
SCENARIO 1 :
The average age of husband, wife and their child - 3 years ago was 27 years.
3 yrs ago was 27 means now = 30 (27+3),
therefore AVERAGE AGE =(H+W+C)/3=30,
By simplifying equation : (H+W+C)=90.
SCENARIO 2:
Wife and the child 5 years ago was 20 years
5YRS ago means now = 25 (20+5).
therefore average = (W+C)/2=25.
By simplifying equation : (W+C)=50.
W=50-C.
Now considering and subtituting in
SCENARIO 1# i.e
(H+W+C) = 90,
H+50-C+C = 90,
H+50 = 90,
H = 90-50,
H = 40.
HENCE B=40 IS The answer.
(1)
Abu Kipa said:
1 year ago
Present age average of H+W+C,
(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)
Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).
Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)
Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).
Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(50)
Shubhanshu said:
2 years ago
3 years ago, the average age of H+W+C was 27.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)
5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.
The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)
5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.
The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
(37)
Saimadhav Thottala said:
2 years ago
Husband + Wife + Child = 27 (years) + 3 (years ago) => 30 x 3 (Members) => 90 years.
And;
Wife + Child = 20 (years) + 5 (years ago) => 25 x 2 (Members) => 50 years.
So,
Husband of present age = ( 90-50 )years.
= 40 years.
And;
Wife + Child = 20 (years) + 5 (years ago) => 25 x 2 (Members) => 50 years.
So,
Husband of present age = ( 90-50 )years.
= 40 years.
(98)
Dptt said:
2 years ago
{(H+W+C)/3} -3 = 27 [(-3) is for 3 years ago].
(H+W+C)/3=30.
H+W+C=90 ---> eqn (1)
{(W+C)/2} -5 = 20 [(-5)is for 5 years ago]
(W+C)/2= 25.
W+C=50 ------> eq(2)
Substitute eq(2) in eq(1),
H+50 =90
so, H = 40 years.
(H+W+C)/3=30.
H+W+C=90 ---> eqn (1)
{(W+C)/2} -5 = 20 [(-5)is for 5 years ago]
(W+C)/2= 25.
W+C=50 ------> eq(2)
Substitute eq(2) in eq(1),
H+50 =90
so, H = 40 years.
(31)
Srihari said:
2 years ago
H + W + C = 27 + 3 = 30(3 years),
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
(35)
Rupesh Kumar Yadav said:
3 years ago
Sum of the present ages of H,W and C = 27 + 3 = 30 So, 30 * 3 = 90Years.
Sum of the present ages of H,W and C = 20 + 5 = 25 So, 25 * 2 = 50Years.
Hence,
Husband of presents age = (90-50)years.
= 40Years.
Sum of the present ages of H,W and C = 20 + 5 = 25 So, 25 * 2 = 50Years.
Hence,
Husband of presents age = (90-50)years.
= 40Years.
(54)
Ruthra said:
4 years ago
Wonderful explanation, thanks @Ramya.
(6)
Manoj Kumar said:
5 years ago
@Varshithtunuguntla.
How obtained here 90 and 40. How did the multiplication?
Can you tell me?
How obtained here 90 and 40. How did the multiplication?
Can you tell me?
(3)
Varshithtunuguntla said:
6 years ago
Your answer is correct. Thanks @Ramya.
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