Aptitude - Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
35 years
40 years
50 years
None of these
Answer: Option
Explanation:

Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.

Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.

Husband's present age = (90 - 50) years = 40 years.

Discussion:
101 comments Page 1 of 11.

Saimadhav Thottala said:   2 years ago
Husband + Wife + Child = 27 (years) + 3 (years ago) => 30 x 3 (Members) => 90 years.
And;
Wife + Child = 20 (years) + 5 (years ago) => 25 x 2 (Members) => 50 years.

So,
Husband of present age = ( 90-50 )years.
= 40 years.
(87)

Rupesh Kumar Yadav said:   3 years ago
Sum of the present ages of H,W and C = 27 + 3 = 30 So, 30 * 3 = 90Years.
Sum of the present ages of H,W and C = 20 + 5 = 25 So, 25 * 2 = 50Years.
Hence,
Husband of presents age = (90-50)years.
= 40Years.
(53)

Abu Kipa said:   1 year ago
Present age average of H+W+C,

(H+W+C)/3 =30 ,since 27 + after 3 years.
=> H+W+C= 90(equation 1)

Present age average of Wife and Child,
(W+C)/2= 25(since 20+ 5 additional years),
=> W+C= 50(equation 2).

Substitution of W+C = 50 in equation 1 gives, H+W+C= 90,
=> H+50= 90 (since W+C= 50).
=> H= 40 years.
(47)

Srihari said:   2 years ago
H + W + C = 27 + 3 = 30(3 years),
H + W + C = 30 * 3 = 90 (3 persons),
W + C = 20 + 5 =25(5 years),
W + C = 25 * 2 = 50(2 persons),
H + W + C - W + C = H.
90 - 50 = 40years.
(34)

Shubhanshu said:   2 years ago
3 years ago, the average age of H+W+C was 27.
The present average age of H+W+C /3 = 30 (each age increment by 3 so 3+3+3/3 =3)

5 years ago, the average age of w+c/2 = 20.
present average age will be w+c/2 = 25.

The present age of the husband will be h+w+c - (w+c) = 90 - 50 = 40.
(34)

Dptt said:   2 years ago
{(H+W+C)/3} -3 = 27 [(-3) is for 3 years ago].
(H+W+C)/3=30.
H+W+C=90 ---> eqn (1)

{(W+C)/2} -5 = 20 [(-5)is for 5 years ago]
(W+C)/2= 25.
W+C=50 ------> eq(2)

Substitute eq(2) in eq(1),
H+50 =90
so, H = 40 years.
(29)

Anant gavas said:   6 years ago
(H+W+C)/3 = 27+3(add 3 to get present data).
H+W+C = 27*3+3*3 = 90.

(W+C)/2 = 20+5(to get present data).
W+C = 20*2+5*2 = 50.

So (H+W+C)-(W+C) = 40 years.
(11)

Ruthra said:   4 years ago
Wonderful explanation, thanks @Ramya.
(5)

Ramya said:   1 decade ago
This is ramya from vizag,can i solve the problem as below as per question,
present ages of hus=h;wife=w;child=c;
---> 3 years ago it was said the avg ages of the hus,wife,child was 27 years.so,
((h-3)+(w-3)+(c-3))/3=27;
so solving it i got h+w+c=90;--->(a)
and given 5 years ago wife and childs age avg=20years so,
i took((w-5)+(c-5))/2=20;solving it i got w+c=50;-->(B)
on solving (a)&(b) i got h age as 40years,can this procedure be correct??
please do reply me?
(3)

Manoj Kumar said:   5 years ago
@Varshithtunuguntla.

How obtained here 90 and 40. How did the multiplication?

Can you tell me?
(3)


Post your comments here:

Your comments will be displayed after verification.