Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
104 comments Page 11 of 11.
Praveen said:
2 decades ago
@vinod ..
h+w+c - w+c =husbands age
27*3 here 27 is average age and 3 is the number (sum is avg*n )
and 3*3 here we are taking after 3 years and into(*) 3 munbers.
h+w+c - w+c =husbands age
27*3 here 27 is average age and 3 is the number (sum is avg*n )
and 3*3 here we are taking after 3 years and into(*) 3 munbers.
Vinod said:
2 decades ago
Ques- The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
, ...
Can anybody explain it easily. because i don't understand that why we took this condition - Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
, ...
Can anybody explain it easily. because i don't understand that why we took this condition - Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sundar said:
2 decades ago
@Renu
The solution for your problem:
Lets take the age of father 10 yrs ago as x.
Then rest of the 5 members 10 yrs ago as y.
Now the mean age 10 yrs ago is = (x + y)/6 --(1)
and now as father is dead and all the ages of the other 5 members has risen by 10 each.
So mean age now =(y + 5(10))/6 ---(2)
Equating (1) and (2): (x+y)/6 = (y+50)/6
Be solving the above, we get x = 50.
So present age when he died
= x + 10
= 60 yrs.
The solution for your problem:
Lets take the age of father 10 yrs ago as x.
Then rest of the 5 members 10 yrs ago as y.
Now the mean age 10 yrs ago is = (x + y)/6 --(1)
and now as father is dead and all the ages of the other 5 members has risen by 10 each.
So mean age now =(y + 5(10))/6 ---(2)
Equating (1) and (2): (x+y)/6 = (y+50)/6
Be solving the above, we get x = 50.
So present age when he died
= x + 10
= 60 yrs.
RENU said:
2 decades ago
Question: When I was married 10 years ago my wife is the 6th member of the family. Today my father died and a baby born to me.The average age of my family during my marriage is same as today. What is the age of Father when he died?
Can anyone help me to find solution for this question AS SOON AS POSSIBLE?
Can anyone help me to find solution for this question AS SOON AS POSSIBLE?
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