Aptitude - Average - Discussion

@priya:
Hi priya. Look into your equation, send 3 to right side which gives the equation, h,w,c are current ages of husband, wife and child respectively....
The average of their ages three years back is as follows.
((h-3)+(w-3)+(c-3))/3=81
==> h+w+c=81+9
==> h+w+c=90 ----(1)(this is the sum of ages of husband, wife and child at present)
And further it is given that, five years back, average of wife and child is 20 years.
i.e. ((w-5)+(c-5))/2=20
==> (w-5)+(c-5)=40
==> w+c=50----(2)

Now, on substituting equation (2) in (1)..
we will get h=90-50 = 40 years.
Hence, the current age of husband is 40 years.
Hope you would get it now.

((h-3)+(w-3)+(c-3))/3=27
h+w+c=90.
how to 90 comes ? I don't understand.

I solved in this method.. Is this right?
Let x,y,z be the age of husband,wife and child respectively..
for the first condition.. we can write 27=((x+y+z)/3)-3
27=(x+y+z-9)/3
81=x+y+z-9
90=x+y+z....equation 1
for the second condition..we can write 20=((y+z)/2)-5
20=(y+z-10)/2
40=(y+z-10)
50=y+z........equation 2
equation1 - equation2 gives x+y+z-y-z=90-50
x=40
i.e husband's age is 40years..

Ramya. Good way to solve, simple to understand.

Let the present age of husband,wife and child be x yrs
3 yrs ago their was x-3
x-3=27
x=30
the sum of their age is 90
5 yrs ago the avg age of wife n child was 20yrs
their present avg age=20+5=25
so,the sum of their present age is 25*2=50
the present age of husband =90-50=40

Yeah truly its very simple. Thanks.

@Ramya:this is one of the simplest way 2 solve such kind of problems..

3 years ago,their avg is 27.
((h-3)+(w-3)+(c-3))/3=27
h+w+c=90.(present)
5 years ago w & c is 20.
((w-5)+(c-5))/2=20
w+c=50.(present)
(h+w+c)-(w+c)=40.
h=40 years

This is ramya from vizag,can i solve the problem as below as per question,
present ages of hus=h;wife=w;child=c;
---> 3 years ago it was said the avg ages of the hus,wife,child was 27 years.so,
((h-3)+(w-3)+(c-3))/3=27;
so solving it i got h+w+c=90;--->(a)
and given 5 years ago wife and childs age avg=20years so,
i took((w-5)+(c-5))/2=20;solving it i got w+c=50;-->(B)
on solving (a)&(b) i got h age as 40years,can this procedure be correct??
please do reply me?

@SUNDER
IN 2nd expression
{y+5(10)}/6 is wrong i think .
it has to be y*10+5*10 divided by 5 i think because father has died so only 5 members will be ther ..