Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
101 comments Page 5 of 11.
Karthy said:
1 decade ago
When the solution is started like this
husband=x,wife=y&child=z
bf4 3yrs x-3+y-3+z-3/3 =27
terefore x+y+z=90--1
bf4 5yrs y-5+z-5/2 =20
terefore y+z=50---2 (1-2)
terefore x=40
husband=x,wife=y&child=z
bf4 3yrs x-3+y-3+z-3/3 =27
terefore x+y+z=90--1
bf4 5yrs y-5+z-5/2 =20
terefore y+z=50---2 (1-2)
terefore x=40
Vasavi said:
1 decade ago
Ramya your way of answering this was very good.
Srinivas said:
1 decade ago
husband+wife+child =3 years ago =27 present age =30 (27+3=30)
wife and child = 5 years ago =20 present age=25 (20+5=25)
h+w+c =3*30=90 -- I
w+c =2*25=50 --II
substract(I-II) 90-50=40 year
wife and child = 5 years ago =20 present age=25 (20+5=25)
h+w+c =3*30=90 -- I
w+c =2*25=50 --II
substract(I-II) 90-50=40 year
Rahul said:
1 decade ago
thanks ramya
Mahesh said:
1 decade ago
h+w+c/3 = 27.
h+w+c = 81.
w+c/2 = 20.
w+c = 40.
h+w+c = 81.
h+40 = 81.
h = 81-40.
h = 40.
h+w+c = 81.
w+c/2 = 20.
w+c = 40.
h+w+c = 81.
h+40 = 81.
h = 81-40.
h = 40.
Murali said:
1 decade ago
Given that average age of husband, wife, child 3 years ago was 27 years
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
average age of wife child 5 years ago was 20 years.
h+w+c/3 = 27.
h+w+c = 81 it is 3 years ago this is eq1.
w+c = 40 it is 5 years ago then it is convert in to 3 years ago i.e adding 2*2 = 4 therefore w+c=44 eq2.
Eq1-eq2 we get h=37 this is 3 years age so add 3 years to get present age
answer is 40 years.
Shah said:
1 decade ago
(3x27)+3 [ 27 is avg. age x 3 family members + 3( ie number years ago) ... Ans comes to 85 years.
(2x20)+5 [ 20 is avg. age of child and mother x 2 + 5( ie number years ago ... Ans comes to 45 years.
Now 85-45 = 40 years.
Is it correct way of solving ?
(2x20)+5 [ 20 is avg. age of child and mother x 2 + 5( ie number years ago ... Ans comes to 45 years.
Now 85-45 = 40 years.
Is it correct way of solving ?
Gopalkrishna said:
1 decade ago
Present age:
H+W+C=30*3.
W+C=25*2.
....................
ie...,H=40 year.
H+W+C=30*3.
W+C=25*2.
....................
ie...,H=40 year.
ALIYAZ said:
1 decade ago
@PRIYA.
[(h-3)+(w-3)+(c-3)/3] = 27.
[(h+w+c-9)/3] = 27.
[(h+w+c)/3]+(9/3) = 27.
[(h+w+c)/3] = 27+3 ====>h+w+c=30*3 ====>h+w+c=90.
Similarly w+c = 50.
[(h-3)+(w-3)+(c-3)/3] = 27.
[(h+w+c-9)/3] = 27.
[(h+w+c)/3]+(9/3) = 27.
[(h+w+c)/3] = 27+3 ====>h+w+c=30*3 ====>h+w+c=90.
Similarly w+c = 50.
Kholofelo said:
1 decade ago
What is algorithm?
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