Aptitude - Average - Discussion
Discussion Forum : Average - General Questions (Q.No. 8)
8.
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:
Answer: Option
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90 - 50) years = 40 years.
Discussion:
104 comments Page 3 of 11.
Ravikumara. said:
6 years ago
a)=(x+y+z)/3 = 27------> (1) given
=(x+y+z) =3*27=81------> (2) 3years back
=(x+y+z) =81+(3*3) =90------> (3) present age.
B) =(x+y) /2= 20------> (4) given
= (x+y) =2*20=40------> (5) 5years back age
= (x+y) =40+(5*2)=50------> (6) present age of wife and child.
= x+y+z =90
= 50+z=90
=90-50 = 40 = z------> Present husband age (Or)
eq-3 subtracting with 6 => 90-50 = 40 husband's present age.
=(x+y+z) =3*27=81------> (2) 3years back
=(x+y+z) =81+(3*3) =90------> (3) present age.
B) =(x+y) /2= 20------> (4) given
= (x+y) =2*20=40------> (5) 5years back age
= (x+y) =40+(5*2)=50------> (6) present age of wife and child.
= x+y+z =90
= 50+z=90
=90-50 = 40 = z------> Present husband age (Or)
eq-3 subtracting with 6 => 90-50 = 40 husband's present age.
(1)
SRIRAM said:
7 years ago
@All.
Take x, y, z intial age is 27 after three years it converted into 30. For three members it is 90.
Then 5 years back 20 years. Calculate with present age it is 25.
Now
X+Y+Z=(3*30)=90.
Y+Z=20(5 years back)Now =(25*2)=50,
Now equate it.
Y+Z cancelled,
X=90-50.
And X=40.
Take x, y, z intial age is 27 after three years it converted into 30. For three members it is 90.
Then 5 years back 20 years. Calculate with present age it is 25.
Now
X+Y+Z=(3*30)=90.
Y+Z=20(5 years back)Now =(25*2)=50,
Now equate it.
Y+Z cancelled,
X=90-50.
And X=40.
Anshal mishra said:
7 years ago
Thanks @Ramya.
(1)
Mukul kalsait said:
7 years ago
20+5 =25 today's average of w+child.
H+w+child is 27 +3 = 30 todays all average.
Difference is 5, So 5*2+ new avg30 = 40.
H+w+child is 27 +3 = 30 todays all average.
Difference is 5, So 5*2+ new avg30 = 40.
(2)
Ameer said:
7 years ago
Thanks for providing the easiest solution @Loverboy.
3 years ago, their avg is 27.
((h-3) + (w-3) + (c-3) ) /3 = 27.
h+w+c = 90. (present).
5 years ago w & c is 20.
((w-5) + (c-5) ) /2 = 20.
w+c=50. (present).
(h+w+c) - (w+c) = 40.
h = 40 years.
3 years ago, their avg is 27.
((h-3) + (w-3) + (c-3) ) /3 = 27.
h+w+c = 90. (present).
5 years ago w & c is 20.
((w-5) + (c-5) ) /2 = 20.
w+c=50. (present).
(h+w+c) - (w+c) = 40.
h = 40 years.
(1)
Rida akram said:
7 years ago
A person has a wife and three children. The average age of his parents is 70 which is 40 to his age and his wife is 15 from the average age of her children. What is the average age of the whole family?
Can anyone solve this?
Can anyone solve this?
(1)
Muskan said:
7 years ago
The average age 3 years ago = x+y+z/3 = 27,
Age of wife and son 5 years ago is x-2+y-2/2 = 20,
Hence x+y = 36.
36+z/3 = 27,
z=45.
Hence present age should be 45+3 which is 48.
Can someone tell me why this is wrong?
Age of wife and son 5 years ago is x-2+y-2/2 = 20,
Hence x+y = 36.
36+z/3 = 27,
z=45.
Hence present age should be 45+3 which is 48.
Can someone tell me why this is wrong?
(1)
Asad Ullah said:
7 years ago
The average age of three persons is 18. If two of them are included then the average age becomes 20. If the age of 1st is 17 then find the age of the remaining persons.
Can anyone tell me?
Can anyone tell me?
Ramesh said:
7 years ago
Your explanation is superb, Thanks @RAMYA.
Nikhil said:
7 years ago
@Kanchan Shah.
Can you give the explanation little briefly?
Can you give the explanation little briefly?
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